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pickupchik [31]
3 years ago
6

You swing your golf club such that it hits a ball with a force of 15 newtons. It makes contact with the ball for a distance of 0

.01 m. What is the work on the ball?
Physics
1 answer:
Viefleur [7K]3 years ago
3 0

Answer:

W = 0.15 J

Explanation:

Given that,

The force acting on the ball, F = 15 N

It makes contact with the ball for a distance of 0.01 m

We need to find the work done on the ball. The work done can be calculated as :

W = Fd

So,

W = (15 × 0.01) J

W = 0.15 J

So, the work done is 0.15 J.

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2.
koban [17]

The question is not well presented.

There is  ______ shift in sound  frequency for observers towards  whom the source is approaching.

Answer:

The  gap should be filled with an apparent upward

Explanation:

The Doppler effect (also referred to as the Doppler shift) is the difference in frequency of a wave when related to an observer who has a relative movement to the wave source

The Doppler effect can be observed to occur with all types of waves - most notably water waves, sound waves, and light waves

The Doppler effect describes sound as an effect which is produced from a moving source of wave.

According to the Doppler effect;

When the source of waves in which there is an apparent upward shift in frequency for observers towards whom the source is approaching.

3 0
4 years ago
While traveling along a highway a driver slows from 24 m/s to 15 m/s in 12 seconds. What is the automobile's acceleration? (Reme
djverab [1.8K]

Considering that while traveling on a road with a<u> final speed of 15 m/s</u>, and an<u> initial speed of 24 m/s</u>, with a given time <u>of 12 seconds.</u>

To calculate the acceleration, we apply the following formula:

α = Vf - Vo/t

We add our data into the formula and solve:

α = 15 m/s - 24 m/s/12 sec

α = -0.75 m/s²

Therefore, the acceleration of the car is -0.75 m/s².

<h2>Skandar</h2>
4 0
2 years ago
A cylinder with a piston contains 0.200 mol of nitrogen at 1.50×105 Pa and 320 K . The nitrogen may be treated as an ideal gas.
Alja [10]

Answer:

Q = -105 J

Also we know that for cyclic process change in internal energy is always ZERO

Explanation:

First gas is compressed isobarically such that its volume is half of initial volume

So its temperature is also half

So heat given in this process is given as

Q = nC_p \Delta T

for diatomic gas we have

C_p = \frac{7}{2} R

so we will have

Q = 0.200(\frac{7}{2}R)(160 - 320)

Q = -930.7 J

Now in adiabatic process heat is not transferred

so in this process

Q = 0

so we have

T_1V_1^{1.4-1} = T_2V_2^{1.4-1}

(160)(\frac{V}{2})^{0.4} = T_2(V)^{0.4}

T_2 = 121.26 K

Now it is again reached to original pressure

so temperature will become initial temperature

so heat given in that part

Q_3 = nC_v\Delta T

here we know that

C_v = \frac{5}{2}R

Q_3 = (0.200)(\frac{5}{2}R)(320 - 121.26)

Q_3 = 825.76 J

So total heat given to the system is

Q = -930.7 + 0 + 825.76

Q = -105 J

Also we know that for cyclic process change in internal energy is always ZERO

3 0
3 years ago
The top of a tower much like the leaning bell tower at Pisa, Italy, moves toward the south at an average rate of 1.4 mm/y. The t
Gemiola [76]

Answer:

\omega=7.16*10^{-13}\frac{rad}{s}

Explanation:

The angular speed is given by:

\omega=\frac{v}{r}

Here v is the linear speed and r is the radius of the circular motion. The height of the tower is equal to the radius of the circular motion of the top of the tower, since is rotating about its base. We need to convert the given linear speed to \frac{m}{s}:

1.4\frac{mm}{y}*\frac{10^{-3}m}{1mm}*\frac{1y}{3.154*10^7s}=4.44*10^{-11}\frac{m}{s}

Now, we calculate the angular speed:

\omega=\frac{4.44*10^{-11}\frac{m}{s}}{62m}\\\omega=7.16*10^{-13}\frac{rad}{s}

8 0
4 years ago
An object starts from rest and falls freely for 40. meters near the surface of planet P. If the time of fall is 4.0 seconds, wha
Sergeu [11.5K]
Let's use the equations for rectilinear motion. One particular equation is:

d = v₀t +(1/2)at²

Since it has been mentioned that the object starts from rest, then v₀ = 0. Substituting the values,

40 m = (0)(4 s) + (1/2)(a)(4 s)²
Solving for a,
a = 5 m/s²

<em>Therefore, the acceleration due to gravity is 5 m/s².</em>
6 0
4 years ago
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