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just olya [345]
3 years ago
15

An object starts from rest and falls freely for 40. meters near the surface of planet P. If the time of fall is 4.0 seconds, wha

t is the magnitude of the acceleration due to gravity on planet P?
Physics
1 answer:
Sergeu [11.5K]3 years ago
6 0
Let's use the equations for rectilinear motion. One particular equation is:

d = v₀t +(1/2)at²

Since it has been mentioned that the object starts from rest, then v₀ = 0. Substituting the values,

40 m = (0)(4 s) + (1/2)(a)(4 s)²
Solving for a,
a = 5 m/s²

<em>Therefore, the acceleration due to gravity is 5 m/s².</em>
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7 0
3 years ago
Monochromatic light of wavelength 687 nm is incident on a narrow slit. On a screen 1.65 m away, the distance between the second
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Answer:

a ) 1.267 radian

b ) 1.084 10⁻³ mm

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=  2.09 /1.65  

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