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dimaraw [331]
3 years ago
10

An automobile accelerates from rest at 2.0 m/s2 for 20 s. The speed is then held constant for 20 s, after which there is an ac-

celeration of -3.0 m/s? until the automobile stops. What is the total distance traveled?
Physics
1 answer:
MaRussiya [10]3 years ago
5 0

Answer:

1446.7m

Explanation:

You need to look at this in 3 separate stages, and then sum thedistance from each stage:

Stage 1)

a=2

t=20

V_0=0

s=V_0t+\frac{1}{2}g t^2

x=400m

We also need to find the final velocity v=a*t=20*2=40m/s

Stage 2)

a=0

v=40

t=20

x=vt

x=800m

Stage 3)

a=-3

v_0\\=40

v=0

v^=v_0^2 + 2 a x\\0=40^2+2*(-3)x\\x=266.7m

So the total distance is x=400+800+266.7=1466.7m

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