Answer:
The rate at which work is done is power
There is no equation here
Answer:
≅50°
Explanation:
We have a bullet flying through the air with only gravity pulling it down, so let's use one of our kinematic equations:
Δx=V₀t+at²/2
And since we're using Δx, V₀ should really be the initial velocity in the x-direction. So:
Δx=(V₀cosθ)t+at²/2
Now luckily we are given everything we need to solve (or you found the info before posting here):
- Δx=760 m
- V₀=87 m/s
- t=13.6 s
- a=g=-9.8 m/s²; however, at 760 m, the acceleration of the bullet is 0 because it has already hit the ground at this point!
With that we can plug the values in to get:
![760=(87)(cos\theta )(13.6)+\frac{(0)(13.6^{2}) }{2}](https://tex.z-dn.net/?f=760%3D%2887%29%28cos%5Ctheta%20%29%2813.6%29%2B%5Cfrac%7B%280%29%2813.6%5E%7B2%7D%29%20%7D%7B2%7D)
![760=(1183.2)(cos\theta)](https://tex.z-dn.net/?f=760%3D%281183.2%29%28cos%5Ctheta%29)
![cos\theta=\frac{760}{1183.2}](https://tex.z-dn.net/?f=cos%5Ctheta%3D%5Cfrac%7B760%7D%7B1183.2%7D)
![\theta=cos^{-1}(\frac{760}{1183.2})\approx50^{o}](https://tex.z-dn.net/?f=%5Ctheta%3Dcos%5E%7B-1%7D%28%5Cfrac%7B760%7D%7B1183.2%7D%29%5Capprox50%5E%7Bo%7D)
I believe the answer to your question is A. 340 meters/second hope i helped
There are three forces acting on the book.
1. Force due to gravity
2. Force exerted downward by the hamster
3. Normal Force in reaction to the downward forces
Since the book is not moving, the net force is zero. The summation of all forces must be zero. Then we could find the normal force which is unknown (denoted as x).
∑F = -(4 kg)(9.81 m/s2) - 3 N + x =0
∑F = -39.24 N - 3N + x =0
x = 42 N
Therefore, the normal force is 42 N.