Answer: He had 14 more touchdowns than he did fumbles.
Step-by-step explanation:
Step 1. Ok, so we need to see how many times 9 will divide into 18.
18/9=2.
Step 2. So now that we know that 9 goes into 18 two times and we know he has two fumbles for every 9 touchdowns we can multiply 2 by 2 to find out how man fumbles he had.
2*2=4
Step 3. Now to find out how many more touchdowns than fumbles he had we need to subtract his fumbles from his touchdowns.
18-4= 14. So, now we know he had 14 more touchdowns than he did fumbles.
Hope this helps!
Answer:
Lateral area =
pi * (radius) * √ [ height ^2 + radius^2 ] =
pi * ( 4 ) * √ [ 4^2 + 3^2 ] =
pi * ( 4 ) * √25 =
pi * ( 4 ) * (5 ) =
20 pi units^2 ≈ 62.8 units^2
Step-by-step explanation:
we are given that
angle(ACF)=90
angle(ACB)=61
sum of all angles along any line is 180
so, we get
angle(ACF)+angle(ACD)=180
we can plug value
90+angle(ACD)=180
angle(ACD)=90
now, we can use formula
angle(ACD)=angle(ACB)+angle(BCD)
now, we can plug values
and we get
90=61+angle(BCD)
90-61=61-61+angle(BCD)
angle(BCD)=29................Answer
Answer:
Yes! I use this site all the time and my questions always get answered quickly!
Step-by-step explanation:
Answer:
0.8%
Step-by-step explanation:
Because they are two independent events, the final probability is the product of the probability of each event.
First event:
The complement of a student being male is that he is female.
Therefore, if 60% is male, the remaining 100% is 40%, meaning that 40% of the students are female.
Second event:
If she's taller than 5'4", we're told she has a 2% chance of being a woman.
Therefore the final probability is:
0.4*0.02 = 0.008
That is, the probability that it is female and that it is over 1.6 meters tall is 0.8%.
