Al S
1) <u> 35.94 </u> =1.33111 <u> 64.06 </u> = 2.001875
27 32
2) = <u> 1.33111 </u> = <u> 2.001875 </u>
1.33111 1.33111
3) = ( 1 ) × 2 = ( 1.5 ) ×2
4) = 2 = 3
Empirical Formula = Al2S3
1) Divide the percentage given in question by the Relative Atomic Mass (RAM)
of the given elements.
2) When you find the answers of the first part of question, divide these once again but this time, by the lowest number you found in part 1.
3) and 4) Write down the values. If you get a decimal which is in between 0.3-0.7 (including the 0.3 and 0.7), you cannot make it a whole number by rounding of. Therefore, multiply the decimal with a whole number until you get a whole number as your answer. In this question, when you multiply 1.5 by 2, the answer is 3 which is a whole number. Multiply the other whole number by the same number as that you multiplied for 1.5. And use these numbers in part 4 to make the empirical formula which is Aluminium Sulfide (Al2S3)
Hope this helps you :)))
Please give this a brainliest
Covalent compounds are generally not very hard because they are formed by two or more nonmetallic atoms.
<h3>COVALENT COMPOUNDS:</h3>
Covalent compounds are compounds whose constituent elements are joined together by covalent bonds.
Covalent bonding occurs when two or more nonmetallic atoms of an element share valence electrons. This means that covalent compounds will not be physically hard since they constitute non-metals.
Examples of covalent compounds are:
- H2 - hydrogen
- H2O - water
- HCl - hydrogen chloride
- CH4 - methane
Learn more about covalent compounds at: brainly.com/question/21505413
Answer: hopefully this is right UwU
Explanation: The infrared spectrum of a sample is recorded by passing a beam of infrared light through the sample. When the frequency of the IR is the same as the vibrational frequency of a bond or collection of bonds, absorption occurs. Examination of the transmitted light reveals how much energy was absorbed at each frequency (or wavelength).
Answer:
Average atomic mass of the vanadium = 50.9415 amu
Isotope (I) of vanadium' s abundance = 99.75 %= 0.9975
Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu
Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025
Atomic mass of Isotope (II) of vanadium ,m' = ?
Average atomic mass of vanadium =
m × abundance of isotope(I) + m' × abundance of isotope (II)
50.9415 amu =50.9440 amu× 0.9975 + m' × 0.0025
m'= 49.944 amu
Explanation:
This certain type of rock is constructive, not only from the fact that it was made up from earthly habits. But also it breaks down very easily, which can help the environment. Therefore a sedimentary rock is constructive.
