Question

Two pro baseball players of the same height are testing how far they can throw. One players throws the ball at a 40.0 degrees angle to the horizontal. The ball leaves his hand at a speed of 36.1 m/s. How far does the ball travel before it lands in the other player's glove

Answer 1

Answer:

The  distance traveled by the ball before it lands in the other player's glove is 130.96 m.

Explanation:

Given;

angle of projection of the ball, θ = 40⁰

initial velocity of the ball, u = 36.1 m/s

The distance traveled by the ball before it lands in the other player's glove is the range of the projectile, calculated as follows;

$R = \frac{u^2 sin(2\theta)}{g} \\\\R= \frac{36.1^2 \times sin(2\times 40)}{9.8} \\\\R = \frac{36.1^2 \times sin(80)}{9.8} \\\\R = 130.96 \ m$

Therefore, the  distance traveled by the ball before it lands in the other player's glove is 130.96 m.