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2 years ago

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A chain of length L has a mass of m which is uniformly distributed. When it is placed on a smooth horizontal table, 1/4 of its l

ength hangs over the edge of the table (as shown in the figure). Then the chain slides away from the table freely, how much gravitational potential energy has changed from the beginning to the chain just sliding away from the table? (The height of the table from the ground is much greater than L)

1 answer:

krok68 [10]2 years ago

6 0

Gravitational potential energy has changed from the beginning to the chain just sliding away from the table willl be MgL/24.

<h3>What is gravitational potential energy?</h3>

The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.

Length of hanging part, L/4

The gravitational potential energy is;

Work = Gravitational potential energy

Work done =force×displacement

$\rm W = \frac{Mg}{3} \times \frac{L}{8} \\\\ W = \frac{MgL}{24}$

Hence, gravitational potential energy has changed from the beginning to the chain just sliding away from the table willl be MgL/24.

To learn more about the gravitational potential energy, refer;

brainly.com/question/3884855

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3 years ago

Read 2 more answers

¿cual es la velocidad de un haz de electrones que marchan sin desviarse cuando pasan a traves de un campo magnetico perpendicula

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Answer:

La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.

Explanation:

Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:

$F = |q|vBsin(\theta)$ (1)

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q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C

v: es la velocidad del haz de electrones =?

B: es el campo magnético = 3500007 T

θ: es el ángulo entre el vector velocidad y el campo magnético = 90°

Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:

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