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ss7ja [257]
2 years ago
15

A chain of length L has a mass of m which is uniformly distributed. When it is placed on a smooth horizontal table, 1/4 of its l

ength hangs over the edge of the table (as shown in the figure). Then the chain slides away from the table freely, how much gravitational potential energy has changed from the beginning to the chain just sliding away from the table? (The height of the table from the ground is much greater than L)

Physics
1 answer:
krok68 [10]2 years ago
6 0

Gravitational potential energy has changed from the beginning to the chain just sliding away from the table willl be MgL/24.

<h3>What is gravitational potential energy?</h3>

The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.

Length of hanging part, L/4

The gravitational potential energy is;

Work = Gravitational potential energy

Work done =force×displacement

\rm W = \frac{Mg}{3} \times \frac{L}{8} \\\\ W = \frac{MgL}{24}

Hence, gravitational potential energy has changed from the beginning to the chain just sliding away from the table willl be MgL/24.

To learn more about the gravitational potential energy, refer;

brainly.com/question/3884855

#SPJ1

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Answer:

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Explanation:

The projectile motion is described by the kinematics equations giving a parabolic trajectory, where on the x axis there is no acceleration and on the y axis the acceleration is the acceleration of gravity.

When the air resistance is taken into account it can be approximated as a force that opposes the movement that for low speeds is proportional to the speed of the space.

Consequently, the movement in the axis and the acceleration is less, in some cases it can be so small that the constant handle speed, in this case, is called terminal velocity.

On the x-axis the friction force creates an acceleration in the negative direction of the movement that the projectile has to brake.

Therefore the resistance of the air makes the movement not parabolic but shorter in each direction.

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3 years ago
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2 years ago
At what speed does a 1,248 kg compact car have the same kinetic energy as a 18,777 kg truck going 26 km/h?
notka56 [123]

The speed of car is 100.8km/h

KE =  \frac{1}{2} m(v \: truck ) {}^{2}

= 0.5 \times 18777 \times  \frac{26}{3.6} \times  \frac{26}{3.6}

= 489708.79j

=  \frac{1}{2}  \times 1248 \times( v \: car) {}^{2}

= 624v {}^{2}

so \: v {}^{2}  =  \frac{489708.7}{624}

= 784

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Hence, the speed of the car is 100.8km/h

learn more about speed from here:

brainly.com/question/28326855

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3 0
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