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Daniel [21]
4 years ago
10

Where would the temperature of the ocean surface water be the lowest hat

Physics
2 answers:
Mazyrski [523]4 years ago
5 0
Where the sun doesn't hit the water directly. hope this helps
Verizon [17]4 years ago
5 0
The temperature would be higher in areas where the sun is directly hitting the water
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An unbalanced force can cause an object to:
Lilit [14]
It'll speed up in the direction it's being pushed unbalanced. Or, it could slow down if applied the right amount of unbalanced power. And finally if the unbalanced push is pushed it could change the direction of it's current motion it was traveling.<span>
</span>
3 0
3 years ago
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Why does a properly adjusted head restraint help prevent head and neck injuries to occupants in rear-end collisions? Explain you
hammer [34]
When a car hits you in a rear end collision, the car initially has a momentum going in one direction. This causes your car to move in the same direction that car was moving even if you were at rest. So, for conservation of momentum, you initially have momentum going in the east direction for example, after the collision, you will have a change in momentum which causes you to have a velocity in the west direction. This is because you are initially at rest and then there is a sudden change in velocity so when you speed up, that momentum causes you to move backwards. If you don't have a properly adjusted neckrest you could may experience whiplash.
7 0
3 years ago
Determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.
ozzi

Answer:

The thrust is 6\times 10^6\ N

Explanation:

Given that,

Mass of gas, m=1.5\times 10^3\ kg

The rate at which the gas is expelling, \dfrac{dv}{dt}=4\times 10^{3}\ m/s

We need to find the thrust produced by the gas.

We know that force is equal to the rate of change of momentum. So,

F=\dfrac{p}{t}

Also, p = mv

F=\dfrac{mv}{t}

So,

F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N

So, the thrust is 6\times 10^6\ N

3 0
4 years ago
A car takes 10 s to go from v = 0 m/s to v = 25 m/s at constant acceleration. If you wish to find the distance traveled using th
german

Initial velocity (u) = 0 m/s

Final velocity (v) = 25 m/s

time taken (t) = 10s

acceleration (a) = ?

Now,

Acceleration is rate of change of velocity, so formula is

a = (v - u)/t

a = (25 - 10)/10

a = 15/10

a = 1.5 m/(s^2)

Use this value of a.

5 0
4 years ago
Which of the following is true about centripetal force? Check all that apply.
Artemon [7]

<u>The following statements are true about centripetal force :</u>

  • Without centripetal force, an object would continue in a straight
  • line.
  • Gravity can be a centripetal force, such as when it pulls a thrown
  • baseball down to the ground.
  • Friction can be a centripetal force, such as when it keeps a car on  the road going around a curve.

Answer: Option A, C, and D

<u>Explanation: </u>

Centripetal Force & Examples-

Centripetal force can be defined as the component of force that acts on an object in a curvilinear motion, directed towards the centre of axis of the circular path. This is the force responsible to pull an object in an inward direction and balance the pace on the path.

In the absence of the centripetal force, an object will either move in the direction of motion or on a straight path instead of moving inwards. It's also called as an "inward Force" as it tends to move the object towards the centre of the curved path.

As an example, a car moving on a circular road accelerates due to its constant change in direction since it's moving on a circular path. Now, the frictional force comes into picture that contributes its component as a centripetal force, pulling it towards the centre of the axis of the circular path.

Hence we can say that when a car turns on a circular path, friction force acts a centripetal force to maintain its motion and direction on the path. Talking about a baseball which is attracted by the gravitational force of the Earth and hence falls on the ground is clearly not the case of centripetal force as the path may not be circular every time and there is not axis of rotation.

Besides centripetal force, there is another force that acts on an object moving on a circular path but not in the inward direction. It is instead, equal and opposite of the centripetal force that draws the object away from the circular path of motion. Hence, it's called the "Outward force".

4 0
3 years ago
Read 2 more answers
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