Answer is: 9623.85 kJ of heat is <span>transferred from iron ingot.
</span>m(Fe) = 24.7 kg · 1000 g/kg = 24700 g; mass of iron ingot.
C = 0.4494 J/g°C; t<span>he specific heat of iron
</span>ΔT = 880°C - 13°C; temperature <span>difference.</span>
ΔT = 867°C.
Q = m·C·ΔT.
Q = 24700 g · 0.4494 J/g°C ·867°C.
Q = 9623856.06 J ÷ 1000J/kJ.
Q = 9623.85 kJ.
For the first one it is C the muscle system
For the second one it is A allow movement in the body
For the third one it is C Skeletal Muscles
Answer:
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Explanation:
As given
60 min = 50 gm (1)
then we know half-life mean half amount decay time
so we can write as the half of 200 is 100 gm hence
T 1/2 = 100 (2)
solving these two equation by cross multiplication we will get
T 1/2 = 120 min
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To convert from atoms of argon to moles of argon, you need to divide by Avogadro's constant.
3.01*10^23 atoms *(1 mole/6.022*10^23 atoms) = 0.500 moles Ar
0.500 moles of Argon is equal to 3.01*10^23 atoms of Argon.