The correct answer that would best complete the given statement above would be the second option. A screw is an inclined plane wrapped around a cylinder. <span>The efficiency of a screw is low because there is more input than output. In other words, it is because of friction. Hope this answer helps.</span>
The word gravity is used to describe the gravitational pull (force) an object experiences on or near the surface of a planet or moon. The gravitational force is a force that attracts objects with mass towards each other. Any object with mass exerts a gravitational force on any other object with mass.
Hope it answers your question!
Brainliest would be nice but of course you don’t gotta :)
Answer:
8.79*10^6 rad/s
Explanation:
To find the frequency of the circular orbit for an electron you use the following expression, for the radius of the trajectory of an electron, that travels trough a constant magnetic field:
(1)
r: radius of the trajectory
m: mass of the electron = 9.1*10^-31 kg
v: speed of the electron = 1.0*10^6 m/s
q: charge of the electron = 1.6*10^-19 C
B: magnitude of the magnetic field = 5.0*10^-5 T
You use the fact that the angular frequency in a circular motion is given by:
![\omega=\frac{v}{r}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7Bv%7D%7Br%7D)
Then, you solve the equation (1) in order to obtain v/r:
![\frac{v}{r}=\omega=\frac{qB}{m}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%7D%7Br%7D%3D%5Comega%3D%5Cfrac%7BqB%7D%7Bm%7D)
Finally, you replace the values of the parameters:
![\omega=\frac{(1.6*10^{-19}C)(5.0*10^{-5}T)}{9.1*10^{-31}kg}\\\\\omega=8.79*10^6\frac{rad}{s}](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B%281.6%2A10%5E%7B-19%7DC%29%285.0%2A10%5E%7B-5%7DT%29%7D%7B9.1%2A10%5E%7B-31%7Dkg%7D%5C%5C%5C%5C%5Comega%3D8.79%2A10%5E6%5Cfrac%7Brad%7D%7Bs%7D)
hence, the angular frequency is 8.79*10^6 rad/s
The frequency is:
![f=2\pi \omega=5.5*10^7Hz](https://tex.z-dn.net/?f=f%3D2%5Cpi%20%5Comega%3D5.5%2A10%5E7Hz)
Answer:
b.
Explanation:
It's b I sis thebksqjwnsx0qkqnsnd991isnd