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LekaFEV [45]
3 years ago
13

What property of stars can be measured only by using binary-star systems?

Physics
1 answer:
drek231 [11]3 years ago
3 0

Answer:

mass

Explanation:

To expect an understanding of the nature and evolution of the stars, astronomers had to try to determine an important parameter: its mass. This is difficult to determine because neither the luminosity measurements nor the spectral analysis are of any help. The only solution is to resort to astrometry, the precise measurement of stellar positions, and apply it to what is called binary systems, that is, pairs of stars linked by their mutual gravitational attraction and in orbit around each other.

In the solar system there is a law, called the third law of Kepler, that connects the size and period of each planetary orbit and that makes the Sun's mass intervene. This law can be generalized in all bodies in orbit, in particular the members of a binary system. Instead of the mass of the Sun, it is the total mass of the couple that counts. Thus, if it was possible to measure the period and size of a binary system by observation, it would be enough to apply this law in order to calculate the total mass of the pair.

To determine the mass of each star, not just that of the couple, the astronomer had to study in more detail the relative movement of the two members. This allowed him to determine the proportion of each star in the total of the couple and finally obtain the mass of each body.

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2.72 N

Explanation:

Step 1:

From the basic formula in electrostatics

F = E * q

where F = Force due to charges

           E = Electric field strength

           q = Charge

Step 2:

From the given question

q= 8.5*10^{-6} C

E = 3.2 * 10^{5} N/C

F = 8.5 * 10^{-6} * 3.2 * 10^{5} = 2.72 N

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A lion chasing a zebra sprints 200 meters in ten seconds what is the lions average speed
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Answer:

Lion Average speed:60 km/h

Explanation:

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A child of mass 25 kg is skating fast, +10 m/s, and tries to get revenge by colliding with the 60 kg adult who is sitting still.
tankabanditka [31]

Answer: -4.4 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum p_{o} must be equal to the final momentum p_{f}:

p_{o}=p_{f} (1)

Where:

p_{o}=m_{1}V_{o}+m_{2}U_{o} (2)

p_{f}=m_{1}V_{f}+m_{2}U_{f} (3)

m_{1}=25 kg is the mass of the child

V_{o}=10 m/s is the initial velocity of the child

m_{2}=60 kg is the mass of the adult

U_{o}=0 m/s is the initial velocity of the adult (it is sitting still)

V_{f} is the final velocity of the child

U_{f}=6 m/s is the final velocity of the adult

Substituting (2) and (3) in (1):

m_{1}V_{o}+m_{2}U_{o}=m_{1}V_{f}+m_{2}U_{f} (4)

Isolating V_{f}:

V_{f}=\frac{m_{1}V_{o}-m_{2}U_{f}}{m_{1}} (5)

V_{f}=\frac{(25 kg)(10 m/s)-(60 kg)(6 m/s)}{25 kg} (6)

Finally:

V_{f}=-4.4 m/s This means the velocity of the child is in the opposite direction

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