W = m g weight of drop
W = q E
m = q E / g = = 3 e E / g
m = 3 * 1.6E-19 * 1.4E4 / 9.8 = 6.96E-16 kg
Answer:
(e) thermal expansion
Explanation:
The density, the heat of fusion and the melting temperature of the metal are determining characteristics to take into account to raise the temperature of the metal from room temperature to the melting temperature. Since they will determine the following:
Density: is the relationship between the mass of a body and the volume it occupies in outer space.
Heat of fusion: The enthalpy of fusion or heat of fusion is the amount of energy needed to make a mole of an element that is at its melting point pass from the solid state to the liquid, at constant pressure.
Melting temperature is defined as the temperature at which the phase transition from the solid state to the liquid occurs at normal atmospheric pressure.
While the dilution of metals will only have an influence on the volume it will occupy but not on the heating process
Answer:
2.2nC
Explanation:
Call the amount by which the spring’s unstretched length L,
the amount it stretches while hanging x1
and the amount it stretches while on the table x2.
Combining Hooke’s law with Newton’s second law, given that the stretched spring is not accelerating,
we have mg−kx1 =0, or k = mg /x1 , where k is the spring constant. On the other hand,
applying Coulomb’s law to the second part tells us ke q2/ (L+x2)2 − kx2 = 0 or q2 = kx2(L+x2)2/ke,
where ke is the Coulomb constant. Combining these,
we get q = √(mgx2(L+x2)²/x1ke =2.2nC
Forehead, Feet and Elbows, if the person is perfect health condition.
Answer:
Explanation:
Given that,
The instantaneous current in the circuit is giveen by :
We need to find the rms value of the current.
The general equation of current is given by :
It means, 
We know that,
So, the rms value of current is 2.12 A.
