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Alex
3 years ago
15

The following true stresses produce the corresponding true plastic strains for a brass alloy: True Stress (psi) True Strain 4930

0 0.11 61300 0.21 What true stress is necessary to produce a true plastic strain of 0.25
Engineering
1 answer:
Verizon [17]3 years ago
5 0

Answer:

64640.92 psi

Explanation:

True stress ( psi )       True strain

49300                          0.11

61300                           0.21

<u>Determine the true stress necessary to produce a true plastic strain of 0.25</u>

бT1 = 49300

бT2 = 61300

бT3 = ?

∈T1 = 0.11

∈T2 = 0.21

∈T3  = 0.25

note : бTi = k ∈Ti^h

∴ 49300 = k ( 0.11 )^h ----- ( 1 )

   61300 = k ( 0.21)^h ------ ( 2 )

solving equations 1 and 2 simultaneously

49300/61300 = ( 0.11 / 0.21 )^h

0.804 = (0.52 )^h

next step : apply logarithm

log  ( 0.804 ) = log(0.52)^h

h = log 0.804 /  log (0.52)

  =  0.33

back to equation 1

49300 = k ( 0.11 )^0.33

k = 49300 / (0.11)^0.33

 = 102138

therefore бT3 = K (0.25)^h

                        = 102138 ( 0.25 )^ 0.33  

                         = 64640.92

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