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sveticcg [70]
3 years ago
15

Please help I'll mark brainliest

Mathematics
2 answers:
sweet [91]3 years ago
8 0
Where is the question?
Damm [24]3 years ago
6 0

Answer:

okay...... where is the question

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Which is true of an adjustable rate mortgage?
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The rate of interest may vary , totally depends on the market value of that agency or company or the financial agency which is providing the mortgage money at certain rate. So, option (B) the interest rate may change depending on the condition of the economy is true statement regarding adjustable rate mortgage.Step-by-step explanation: hope it helps

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Which of the tables is a function?<br> PLEASE HELP<br> 15 POINTS <br> or Brainlist answer!!!
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3 years ago
1. What does it mean when we say, find the "mean" of the data? Answer in a complete sentence.
Ber [7]

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Step-by-step explanation: add up all your numbers then you divided by the number of digits you have for example:

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5 0
3 years ago
PLEASE HELP!
Aleks04 [339]

Answer:

Option c:

0.25 \pm 1.645\sqrt{\frac{0.25*(1-0.25)}{90}}

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

For this problem, we have that:

You have access to first year enrolment records and you decide to randomly sample 119 of those records. You find that 89 of those sampled went on to complete their degree. This means that n = 119, \pi = \frac{89}{119} = 0.7478.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

Sample of 90 people with a sample proportion of 0.25

This means that n = 90, p = 0.25.

Confidence interval:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

0.25 \pm 1.645\sqrt{\frac{0.25*(1-0.25)}{90}}

Which is option c.

6 0
3 years ago
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