Answer:
1.67g/cm3
Explanation:
The formula for density is 
. The m variable stands for mass and the v variable stands for volume.
The mass of the brown sugar is 10.0g and the volume is 6.0cm3, so we can plug those values into the equation.
Rounded to 3 significant figures, the density of the block of brown sugar is 1.67 g/cm3. If the mass is in grams and the volume is in cm3, the unit for the final answer is (grams per centimetres cubed).
Answer:
ΔU = −55.45 kJ
Explanation:
From first law of thermodynamics in chemistry, we have;
ΔU = Q + W
where;
ΔU is change in internal energy
Q is the net heat transfer
W is the net work done
We are given;
Q = 74.6 kJ
But Q will be negative since heat is released
Thus;
ΔU = -74.6 kJ + W
We are given;
Constant pressure; P = 35 atm = 35 × 101325 = 3546375 N/m²
Volume before reaction; Vi = 8.2 L = 0.0082 m³
Volume after reaction; V_f = 2.8 L = 0.0028 m³
Now,
W = -P(V_f - V_i)
W = - 3546375(0.0028 - 0.0082)
W = 19.15 KJ
Thus;
ΔU = Q + W
ΔU = -74.6 kJ + 19.15 KJ =
ΔU = −55.45 kJ
Answer:
—96.03°C
Explanation:
We'll begin by writing out the information provided by the question. This includes:
Number of mole (n) = 0.645 mole
Volume (V) = 2.00 L
Pressure (P) = 4.68 atm
Temperature (T) =?
Recall: that the gas constant = 0.082atm.L/Kmol
With the ideal gas equation PV = nRT, the temperature of the gas can be obtained as follow:
PV = nRT
4.68 x 2 = 0.645 x 0.082 x T
Divide both side 0.645 x 0.082
T = (4.68 x 2) /(0.645 x 0.082)
T = 176.97 K
Now, We can also express the temperature obtained in celsius as shown below:
Temperature (celsius) = temperature (Kelvin) - 273
Temperature (celsius) = 176.97 - 273
Temperature (celsius) = —96.03°C
The temperature of the Neon gas is
—96.03°C
Answer:
The element with electron configuration 1s² 2s² 2p⁶ will most likely not........
Explanation:
