At the time that I'll call ' Q ', the height of the stone that was
dropped from the tower is
H = 50 - (1/2 G Q²) ,
and the height of the stone that was tossed straight up
from the ground is
H = 20Q - (1/2 G Q²) .
The stones meet when them's heights are equal,
so that's the time when
<span>50 - (1/2 G Q²) = 20Q - (1/2 G Q²) .
This is looking like it's going to be easy.
Add </span><span>(1/2 G Q²) to each side.
Then it says
50 = 20Q
Divide each side by 20: 2.5 = Q .
And there we are. The stones pass each other
2.5 seconds
after they are simultaneously launched.
</span>
I think this is the solution:
1: U-1, F,-4
2: Na-6, Mo-1, O-4
3: Bi-1, O-1, C-1, I-1
4: In-9, N-1
5: N-2, H-4, S-1, C-1
6: Ge- 15, N-4
7: N-1, H-4, C-1, I-1, O-3
8: H-7, F-1
9: N-1, O-5, H-1, S-1
10: H-8
11: Nb-1, O-1, C-1, I-3
12: C-3, F-3, S-1, O-3, H-1
13: Ag-1, C-1, N-1, O-1
14: Pb-6, H-1, As-1, O-4
Answer:
Explanation:
Velocity can be found using the following formula:
where p is the momentum and m is the mass.
The woman has a mass of 55 kilograms and a momentum of 200 kilogram meters per second.
Substitute the values into the formula.
Divide. Note that the kilograms, or kg, will cancel each other out.
The woman's velocity is 3.63636364 meters per second.
Answer:
ω₂ = 1.9025 x 10⁻⁶ rad/s
Explanation:
given,
mass of star = 1.61 x 10³¹ kg
angular velocity = 1.60 x 10⁻⁷ rad/s
diameter suddenly shrinks = 0.29 x present size
r₂ = 0.29 r₁
using conservation of angular momentum
I₁ ω₁ = I₂ ω₂
ω₂ = 1.9025 x 10⁻⁶ rad/s
