Answer:
No temperature change occurs from heat transfer if ice melts and becomes liquid water (i.e., during a ... to change 1 kg of liquid water at the normal boiling point (100ºC at atmospheric pressure) to steam (water vapor).
The melting point of lead is 327.3o C. Assume the final temperature of the system is T. Then the amount of energy released by the lead as it solidifies is. ΔQ = mleadLlead = 0.09 kg*(2.45*104 J/kg) = 2205 J
Answer:
2.58 x 10⁸ m/s
Explanation:
Time dilation fomula will be applicable here, which is given below.
t = \frac{T}{\left ( 1-\frac{v^2}{c^2} \right )^\frac{1}{2}}
Where T is dilated time or time observed by clock in motion , t is stationary time , v is velocity of clock in motion and c is velocity of light .
c is 3 times 10⁸ ms⁻¹ , T is 7.24 h , t is 3.69 h. Put these values in the formula
7.24 = \frac{3.69}{\left ( 1-\frac{v^2}{c^2} \right )^\frac{1}{2}}\\
\frac{v^2}{c^2}=0.744\\\\
v=2.58\times 10^8
Part A:
To answer this item, we need to convert the given revolutions per minute in speed expressed as miles per hour. In order to do so, we need to use the dimensional analysis and the appropriate conversion factor.
We calculate the circumference that is covered by the wheel.
C = πD
where C is the circumference and D is the diameter.
Substitute the known values,
C = π(26 in) = 81.68 inches
The speed tested is calculated below.
s = (81.68 inches/rev)(480 rev/min)(1 mil/63360 inches)(60 min/1 hr)
s = 37.127 mil/h
<em>ANSWER: 37.127 mil/h</em>
Part B:
Similar to what was done in Part A, the setting of the balancer is calculated below,
setting = (80 mil/h)(1h/60 min)(63360 in/1 mil)(1 rev/81.68 in)
setting = 1034.23 rev/min
<em>ANSWER: 1034.23 rev/min</em>
Answer:
non-accelerated movement
velocity versus time a horizontal straight line.
distance versus time gives a horizontal straight line.
accelerated motion
graph of velocity versus time s an inclined line and the slope
graph of distance versus time is a parabola of the form
Explanation:
In kinematics there are two types of steely and non-accelerated movements
In a the velocity of the body is constant therefore a speed hook against time gives a horizontal straight line.
A graph of distance versus time is a straight line whose slope is the velocity of the body
x = v t
In an accelerated motion the velocity changes linearly with time, so a graph of velocity versus time is an inclined line and the slope is the value of the acceleration of the body
v = v₀ + a t
A graph of distance versus time is a parabola of the form
x =v₀ t + ½ a t²
Answer:
Her error was that she did not subtract 12 from 8 correctly
Explanation:
Jackie did 8-12 instead of 12-8
