The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.
Answer:
Sound waves are pushed closer together, decreasing wavelength
and increasing frequency.
Answer: 1.13 X 10^3 g or 1130 g
Explanation: When you add up everything, you will get 1134.1288 g = 1.11341218 X 10^3. But while adding significant figures, we always look for the least significant figures (here 4.65 has least sig. figures i.e. 3) and take that as a reference to how many significant figures we should have in the answer. (Pretty hard to explain!) Hope you got it!!
Answer:
a) m = 10 and b) λ = 3.119 10⁻⁷ m
Explanation:
In the diffraction experiments the maximums appear due to the interference phenomenon modulated by the envelope of the diffraction phenomenon, for which to find the number of lines within the maximum diffraction center we must relate the equations of the two phenomena.
Interference equation d sin θ = m λ
Diffraction equation a sin θ = n λ
Where d is the width between slits (d = 0.2 mm), a is the width of each slit (a = 0.02 mm). θ is the angle, λ the wavelength, m and n are an integer.
Let's find the relationship of these two equations
d sin θ / a sin θ = m Lam / n Lam
The first maximum diffraction (envelope) occurs for n = 1, let's simplify
d / a = m
Let's calculate
m = 0.2 / 0.02
m = 10
This means that 10 interference lines appear within the first maximum diffraction.
b) let's use the interference equation, remember that the angles must be given in radians
θ = 0.17 ° (π rad / 180 °) = 2.97 10⁻³ rad
d sin θ = m λ
λ = d sin θ / m
λ = 0.2 10⁻³ sin (2.97 10⁻³) / 2
λ = 3.119 10⁻⁷ m
Lifting a mass to a height, you give it gravitational potential energy of
(mass) x (gravity) x (height) joules.
To give it that much energy, that's how much work you do on it.
If 2,000 kg gets lifted to 1.25 meters off the ground, its potential energy is
(2,000) x (9.8) x (1.25) = 24,500 joules.
If you do it in 1 hour (3,600 seconds), then the average power is
(24,500 joules) / (3,600 seconds) = 6.8 watts.
None of these figures depends on whether the load gets lifted all at once,
or one shovel at a time, or one flake at a time.
But this certainly is NOT all the work you do. When you get a shovelful
of snow 1.25 meters off the ground, you don't drop it and walk away, and
it doesn't just float there. You typically toss it, away from where it was laying
and over onto a pile in a place where you don't care if there's a pile of snow
there. In order to toss it, you give it some kinetic energy, so that it'll continue
to sail over to the pile when it leaves the shovel. All of that kinetic energy
must also come from work that you do ... nobody else is going to take it
from you and toss it onto the pile.
