The planet Mercury. Hope this helps
Answer:
175.5 kN
Explanation:
We find the acceleration of the Airbus A320 jetliner from,
a = (v - u)/t where u = initial velocity of jetliner = 0 m/s (since it starts from rest), v = final velocity of jetliner = 82 m/s and t = time for velocity change = 35 s
So a = (v - u)/t = (82 m/s - 0 m/s)/35 s = 82 m/s ÷ 35 s = 2.34 m/s²
Now, the thrust of the engines on the jetliner T = ma where m = mass of jetliner = 75,000 kg and a = acceleration of jetliner = 2.34 m/s²
T = ma
= 75,000 kg × 2.34 m/s²
= 175500 N
= 175.5 kN
The force exerted by student A with his scooter is 306 N and that of student B is 204 N.
<h3>
Force applied by each student</h3>
The force exerted by each student is calculated from Newton's second law of motion.
F = ma
where;
- m is mass
- a is acceleration
F(A) = 127.5 x 2.4
F(A) = 306 N
F(B) = 120 x 1.7
F(B) = 204 N
Thus, the force exerted by student A with his scooter is 306 N and that of student B is 204 N.
Learn more about force here: brainly.com/question/12970081
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You need to know the mass number to work it out. I can see you have it but it's not visible on your photo.
Every proton weighs 1 and every neutron weighs 1 so if you know the total mass of the nucleus and the number of protons, then you can do:
Mass Number - Proton Number = Neutron Number
because the rest of the mass (that isn't from the protons) must come from the neutrons. Make sense?
Answer:
3,237.78N
Explanation:
According to Newton's second law of motion
F = mass * acceleration
Since a = v-u/t
F = m(v-u)/t
Given
Mass m = 0.155kg
v = 50.0m/s
u = -44.0m/s
Time t = 0.00450secs
Substitute
F = 0.155(50-(-44))/0.00450
F = 0.155(50+44)/0.00450
F = 0.155(94)/0.00450
F = 14.57/0.00450
F = 3,237.78N
hence he hit the baseball with a force of 3,237.78N
