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leonid [27]
3 years ago
14

Lc circuit consists of a 20.0 mh inductor and a 0.150 µf capacitor. if the maximum instantaneous current is 0.400 a, what is the

greatest potential difference across the capacitor?
Physics
1 answer:
slavikrds [6]3 years ago
5 0
The following expression is applicable:

Max. inductor energy = Max. capacitor energy

Where;
Max. inductor energy = LI^2/2, with L = 20.0 mH, I = 0.400 A
Max. capacitor energy = CV_max^2/2, C = 0.150 micro Faraday, V_max = Max. potential difference

Substituting;
LI^2/2 = CV^2/2
LI^2 = CV^2
V^2 = (LI^2)/C
V_max = Sqrt [(LI^2)/C] = Sqrt [(20*10^-3*0.4^2)/(0.15*10^-6)] = 146.06 V
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Based on the given, this is probably a gravitational potential energy problem (PEgrav). The formula for PEgrav is:

PEgrav = mgh

Where:
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With this formula you can derive the formula for your unknown, which is mass. First put in what you know and then solve for what you do not know.

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Do operations that you can with what is given first.

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Transpose the 100 to the other side of the equation. Do not forget that when you transpose, you do the opposite operation.

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