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liberstina [14]
3 years ago
7

1. What do you notice from the picture?2. Did anyone get the correct answer? ​

Physics
1 answer:
Fudgin [204]3 years ago
6 0

Answer:

1. I notice nothing because is no picture it probably didnt work

2. idk

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For a certain spring, k = 15N/m. A weight is hung from the spring, stretching it from 0.3m to 0.4m. What force did the weight pr
Mashcka [7]
The stretch of the spring is
\Delta x = 0.4 m-0.3 m=0.1 m
The constant of the spring is k=15 N/m, so we can find the force produced by the weight by using Hook's law:
F=k\Delta x=(15 N/m)(0.1 m)=1.5 N
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What must be attached to each carburetor on a gasoline inboard engine?
alekssr [168]
To each carburetor on a gasoline inboard engine a backfire flame arrestor must be attached.This arrestor will <span>prevent flames from the backfire causing a fire on board.  Several things are important in order the backfire arrestor to function properly: 
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3 years ago
A family shares the same hairdryer.
IceJOKER [234]

Answer:

Idk I’m sorry

Explanation:

Sorry

7 0
3 years ago
Lab: newton's laws of motion assignment: lab report
poizon [28]

Newton's motion laws state that if an object is at rest or in movement, it will tend to maintain its basal state.

<h3>What are Newton's motion laws?</h3>

Newton's motion laws are a set of scientific statements aimed at explaining the physical property of movement.

These laws explain why objects in movement tend to maintain the same velocity for a short period of time.

In conclusion, Newton's motion laws state that if an object is at rest or in movement, it will tend to maintain its basal state.

Learn more about Newton's motion laws here:

brainly.com/question/10454047

#SPJ1

8 0
1 year ago
A lab cart with a mass of 15 kg is moving with constant velocity, v, along a straight horizontal track. A student drops a 2 kg m
lbvjy [14]

The equation 15v_{i} + 2*0 = (15 + 2)v_{f} (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.  

The horizontal momentum is given by:

p_{i} = p_{f}

m_{1}v_{1}_{i} + m_{2}v_{2}_{i} = m_{1}v_{1}_{f} + m_{2}v_{2}_{f}

Where:

  • m₁: is the mass of the lab cart = 15 kg
  • m₂: is the <em>mass </em>of the object dropped = 2 kg
  • v_{1}_{i}: is the initial velocity of the<em> lab cart </em>
  • v_{2}_{i}: is the <em>initial velocit</em>y of the <em>object </em>= 0 (it is dropped)
  • v_{1}_{f}: is the final velocity of the<em> lab cart </em>
  • v_{2}_{f}: is the <em>final velocity</em> of the <em>object </em>

Then, the horizontal momentum is:

15v_{1}_{i} + 2*0 = 15v_{1}_{f} + 2v_{2}_{f}

When the object is dropped into the lab cart, the final velocity of the lab cart and the object <u>will be the same</u>, so:

15v_{1}_{i} + 2*0 = v_{f}(15 + 2)

Therefore, the equation 15v_{i} + 2*0 = (15 + 2)v_{f} represents the horizontal momentum (option 3).

Learn more about linear momentum here:

  • brainly.com/question/2141713?referrer=searchResults
  • brainly.com/question/2400186?referrer=searchResults

I hope it helps you!            

4 0
3 years ago
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