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docker41 [41]
3 years ago
12

Which metal cations form a white precipitate with both H2SO4(aq) and Na2S2O4(aq)? 1. Ba2+ 2. Sr2+ 3. Fe2+ 4. Cu2+

Chemistry
1 answer:
8090 [49]3 years ago
6 0

Answer:

1. Ba2+ 2. Sr2+

Explanation:

When a solution contains the Barium ,Ba²⁺ ion or Strontium, Sr²⁺ ion, they reacts with either H₂SO₄(aq) or Na₂SO₄(aq) to produce a white precipitate of BaSO₄(s) and SrSO₄(s) respectively

The chemical reactions are given below

Ba²⁺ +  H₂SO₄(aq) ⇒ BaSO₄(s) + 2H⁺ (aq)

Ba²⁺ +  Na₂SO₄(aq) ⇒ BaSO₄(s) + 2Na⁺ (aq)

Sr²⁺ +  H₂SO₄(aq) ⇒ SrSO₄(s) + 2H⁺ (aq)

Sr²⁺ +  Na₂SO₄(aq) ⇒ SrSO₄(s) + 2Na⁺ (aq)

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Answer:

  • <u><em>a. C₂H₄</em></u>

Explanation:

At constant pressure and temperature, the mole ratio of the gases is equal to their volume ratio (a consequence of Avogadro's law).

Hence, the <em>complete combustion reaction</em> that has a ratio of 100 ml of gaseous hydrocarbon to 300 ml of oxygen, is that whose mole ratio is 1 mol hydrocarbon : 3 mol of oxygen.

Then, you must write the balanced chemical equations for the complete combustion of the four hydrocarbons in the list of choices, and conclude which has such mole ratio (1 mol hydrocarbon : 3 mol oxygen).

A complete combustion reaction of a hydrocarbon is the reaction with oxygen that produces CO₂ and H₂O, along with the release of heat and light.

<u>a. C₂H₄:</u>

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Precisely, for this reaction the mole ratio is 1 mol C₂H₄: 2 mol O₂, hence, this is the right choice.

The following analysis just shows that the other options are not right.

<u>b. C₂H₂:</u>

  • 2C₂H₂ (g) + 5O₂ (g) → 4CO₂(g)  + 2H₂O (g)

The mole ratio for this reaction is 2 mol C₂H₂ :5 mol O₂.

<u>с. С₃Н₈</u>

  • C₃H₈ (g) + 5O₂ (g) → 3CO₂(g)  + 4H₂O (g)

The mole ratio is 1 mol C₃H₈ : 5 mol O₂

<u>d. C₂H₆</u>

  • 2C₂H₆ (g) +7 O₂ (g) → 4CO₂(g)  + 6H₂O (g)

The mole ratio is 2 mol C₂H₆ : 7 mol O₂

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Explanation:

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