Answer and explanation:
A) An ideal fuel must:
- easy to transport and storage.
- have a high calorific value.
B) The <em>calorific value</em> for a fuel is the amount of heat - measured in Joules- which is produced during the complete combustion of the fuel. It is expressed in Joules per Kg of fuel (J/kg).
C) From the data:
mass of fuel = 2 kg
heat produced = 48,000 KJ
We calculate the calorific value by dividing the heat produced by the mass of fuel, as follows:
calorific value = heat produced/mass of fuel = (48,000 KJ)/(2 kg)= 24,000 kJ/kg
Since 1 KJ= 1000 J, we can express the calorific value in J/kg as follows:
24,000 kJ/kg x 1000 J/1 kJ = 2.4 x 10⁷ J/kg
Answer:
The most state has the high volume is the gas state.
So here the answer is vaporization!!!!
Explanation:
The most state has the high volume is the gas state.
So here the answer is between vaporization and sublimation???
and when the sublimation is: the change of the material from the solid state to the gas state directly without pass to liquid state from the solid first then to the gas
and the vaporization is : The change of the material from the liquid state to the gas state by heating Ex: water vaporize at 100°
here, the answer is sublimation because the difference of volume which resulted from this process is more than the volume resulted from vaporization.
Plz mark brainlist!!
Double bonds are not formed by chlorine. To complete its octet, oxygen requires two bonds (two single bonds or one double bond) and two lone pairs.
Chlorine can only form single bonds unless, for instance, it is bonded to oxygen (ClO3H), in which case, the oxygen forces chlorine to form double bonds.
The chemical element chlorine has the atomic number 17 and the symbol Cl. The second-lightest halogen, fluorine is situated between bromine and fluorine in the periodic table and has most of its features in the middle. At room temperature, chlorine is a gas that is yellow-green.
To know more about Chlorine, visit;
brainly.com/question/14962130
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Answer:
(4) 266 moles
Explanation:
We have Dinitrogen Pentoxide N2O5
6.41*10^25 molecules are given
No of Moles of N2O5 = 
= 
= 106.5 mol
Now using Unitary Method
2 Mole of Nitrogen pentoxide require 5 mole of Oxygen to form N2O5
1 mole of N = 
In 106.5 mole of N = 
= 266.25 mole
So, 6.41*10^25 molecules of N2O5 will require 266.25 mole of Oxygen atoms.
