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Wewaii [24]
3 years ago
9

In estimating the mean speed of a roadway segment,a pilot sample of 100 vehicles at this location yield a sample standard deviat

ion of 4.8 miles/ hr
Engineering
1 answer:
Oxana [17]3 years ago
8 0

Answer:

See Explanation

Explanation:

Given

n = 100

\sigma= 4.8

Required

The question is incomplete.

Given the sample size and the standard deviation, a likely question could be to calculate the standard error (SE) of the mean

This is calculated as:

SE = \frac{\sigma}{\sqrt n}

Substitute values

SE = \frac{4.8}{\sqrt{100}}

Take the positive square root of 100

SE = \frac{4.8}{10}

SE = 0.48

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Two automobiles A and B, of mass mA and mB, respectively are traveling in opposite directions when they collide head on. The imp
Novosadov [1.4K]

Answer:

EA = 180KJ

EB = 320KJ

Where EA and EB, are the energy absorbed by automobile A and by automobile B

Explanation:

The concept of momentum and energy is applied here as it relates to elastic and inelastic collision.

The detailed steps, mathematical manipulation and appropriate substitution is as shown in the attached file.

8 0
4 years ago
Read 2 more answers
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denis23 [38]
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8 0
3 years ago
A technician needs to check the heating operation of a heat pump that has no gauge access ports. The technician should start by:
OverLord2011 [107]

The technician should start by checking the temperature rise across the indoor coil.

<h3>Who is a technician?</h3>

This is a person who has skill in a particular area of job. A technician is responsible for repairs and also ensure different equipment and systems are working perfectly.

Hence, the technician should start by checking the temperature rise across the indoor coil.

Learn more about technician here : brainly.com/question/13315405

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7 0
2 years ago
A polymeric extruder is turned on and immediately begins producing a product at a rate of 10 kg/min. An operator realizes 20 min
hodyreva [135]

Answer:

The plot of the function production rate m(t) (in kg/min) against time t (in min) is attached to this answer.

The production rate function M(t) is:

m(t)=[H(t)\cdot10+H(t-20)\cdot5-H(t-80)\cdot14+H(t-81)\cdot9]kg/min (1)

The Laplace transform of this function is:

\displaystyle m(s)=[\frac{10+5e^{-20s}-14e^{-80s}+9e^{-81s}}{s}]kg/min    (2)

Explanation:

The function of the production rate can be considered as constant functions by parts in the domain of time. To make it a continuous function, we can use the function Heaviside (as seen in equation (1)). To join all the constant functions, we consider at which time the step for each one of them appears and sum each function multiply by the function Heaviside.

For the Laplace transform we use the following rules:

\mathcal{L}[f(x)+g(x)]=\mathcal{L}[f(x)]+\mathcal{L}[g(x)]=F(s)+G(s)    (3)

\mathcal{L}[aH(x-b)]=\displaystyle\frac{ae^{-bs}}{s}    (4)

4 0
4 years ago
Determine the carburizing time necessary to achieve a carbon concentration of 0.30 wt% at a position 4 mm into an iron–carbon al
Ahat [919]

Answer:

the carburizing time necessary to achieve a carbon concentration is 31.657 hours

Explanation:

Given the data in the question;

To determine the carburizing time necessary to achieve the given carbon concentration, we will be using the following equation:

(Cs - Cx) / (Cs - C0) = ERF( x / 2√Dt)

where Cs is Concentration of carbon at surface = 0.90

Cx is Concentration of carbon at distance x = 0.30 ; x in this case is 4 mm = ( 0.004 m )

C0 is Initial concentration of carbon = 0.10

ERF() = Error function at the given value

D = Diffusion of Carbon into steel

t = Time necessary to achieve given carbon concentration ,

so

(Cs - Cx) / (Cs - C0) = (0.9 - 0.3) / (0.9 - 0.1)

= 0.6 / 0.8

= 0.75

now, ERF(z) = 0.75; using ERF table, we can say;

Z ~ 0.81; which means ( x / 2√Dt) = 0.81

Now, Using the table of diffusion data

D = 5.35 × 10⁻¹¹ m²/sec at (1100°C) or 1373 K

now we calculate the carbonizing time by using the following equation;

z = (x/2√Dt)

t is carbonizing time

so we we substitute in our values

0.81 = ( 0.004 / 2 × √5.35 × 10⁻¹¹ × √t)

0.81 = 0.004 / 1.4628 × 10⁻⁵ × √t

0.81 × 1.4628 × 10⁻⁵ × √t = 0.004

1.184868 × 10⁻⁵ × √t = 0.004  

√t = 0.004 / 1.184868 × 10⁻⁵

√t = 337.5903

t = ( 337.5903)²  

t = 113967.21 seconds

we convert to hours

t = 113967.21 / 3600

t = 31.657 hours

Therefore, the carburizing time necessary to achieve a carbon concentration is 31.657 hours

7 0
3 years ago
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