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Lena [83]
3 years ago
5

Josh and jake are both helping to build a brick wall which is 6 meters in height. They each lay 250 bricks, but josh finishes th

is task in 3 hours while jake requires 4.5 hours to complete his part. Who does more work, or do they both do the same amounth? Who has more power? Explain.
Physics
1 answer:
Yakvenalex [24]3 years ago
6 0
Each laid 250 bricks but while Jake was
still working, Josh was lounging in the
shade. Josh has more power but that
power was only on for 3 hours out of 4.5.
Obviously Josh could get more done is less
time as long as he keeps working. Jake will
get the hang of it soon.
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You are trying to decide between two new stereo amplifiers. One is rated at 130 W per channel and the other is rated at 200 W pe
NARA [144]

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The sound level will be 1.870 dB louder.

Explanation:

Given that,

Power = 130 W

Power = 200 W

We need to calculate the sound level

Using formula of sound level

I_{dB}=10\log(\dfrac{I}{I_{0}})

For one amplifier,

I_{1}=10\log(\dfrac{130}{I_{0}})...(I)

For other amplifier,

I_{2}=10\log(\dfrac{200}{I_{0}})...(II)

For difference in dB levels

I_{2}-I_{1}=10\log(\dfrac{200}{I_{0}})-10\log(\dfrac{130}{I_{0}})

I_{2}-I_{1}=10\log(\dfrac{200}{I_{0}}\times\dfrac{I_{0}}{130})

I_{2}-I_{1}=10\log(\dfrac{200}{130})

I_{2}-I_{1}=1.870\ dB

Hence, The sound level will be 1.870 dB louder.

7 0
3 years ago
An uncharged capacitor is connected to the terminals of a 4.0 V battery, and 9.0 μC flows to the positive plate. The 4.0 V batte
Lelechka [254]

Answer:

2.25\mu C

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V = 5.0 V

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Since the capacitor has been connected exactly as before, we have that the charge on the positive plate has increased from 9.0 \mu C to 11.25 \mu C. Therefore, the additional charge that moved to the positive plate is

\Delta Q = 11.25 \mu C-9.0 \mu C=2.25 \mu C

5 0
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