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Usimov [2.4K]
3 years ago
9

PLEASE HELP ME TAKE SOO LONG! (ima fail this test!) its a study guide!

Chemistry
1 answer:
kakasveta [241]3 years ago
6 0

I think it might be C or D

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A compound A has prominent infrared absorptions at 1050, 1786, and 1852 cm–1 and shows a single absorption in the proton NMR spe
olya-2409 [2.1K]

Answer:

Compound A is succinic anhydride and B is methyl succinate (the monomethyl ester).

Structural Diagram is attached.

Explanation:

A.

Succinic anhydride appears as colorless needles or white crystalline solid. ... Succinic anhydride, also called dihydro-2, 5-furandione, is an organic compound with the molecular formula C4H4O3. It is the acid anhydride of succinic acid.

B.

Monomethyl succinate is a dicarboxylic acid monoester that is succinic acid in which one of the carboxy groups has been converted to its methyl ester. It is a dicarboxylic acid monoester and a hemisuccinate. ... They have the general structure RC(=O)OR', where R=fatty aliphatic tail or organyl group and R'=methyl group.

4 0
3 years ago
4. Magnesium and oxygen undergo a chemical reaction to
erastovalidia [21]

Answer:

About 16.1 grams of oxygen gas.

Explanation:

The reaction between magnesium and oxygen can be described by the equation:
\displaystyle 2\text{Mg} + \text{O$_2$} \longrightarrow 2\text{MgO}

24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.

Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:

  1. Convert grams of MgO to moles of MgO.
  2. Moles of MgO to moles of O₂
  3. And moles of O₂ to grams of O₂.

The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.

Dimensional analysis:

\displaystyle 40.5\text{ g MgO} \cdot \frac{1\text{ mol MgO}}{40.31\text{ g MgO}} \cdot \frac{1\text{ mol O$_2$}}{2\text{ mol MgO}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}

In conclusion, about 16.1 grams of oxygen gas was reacted.

You will obtain the same result if you compute with the 24.4 grams of Mg instead:

\displaystyle 24.4\text{ g Mg}\cdot \frac{1\text{ mol Mg}}{24.31\text{ g Mg}} \cdot \frac{1\text{ mol O$_2$}}{1\text{ mol Mg}} \cdot \frac{32.00\text{ g O$_2$}}{1\text{ mol O$_2$}} = 16.1\text{ g O$_2$}

3 0
2 years ago
What is the reducing agent in the reaction below?
frez [133]
Option (a) is correct.
A reducing agent is the one which loses electrons to other substance and an oxidizing agent is one which accepts electrons. 
Here, In CrO_{3}, Cr has oxidation number 6+  in the L.H.S of the equation, but on R.H.S its oxidation number is 0 i.e. it Cr has gained electrons such that total charge is 0.
And the oxidation state of Al in the left-hand side of equation is 0 and in right-hand side, it is +6.i.e. it has donated its electrons to Cr. 

Hence, Cr is the oxidizing agent and Al is the reducing agent. 
4 0
4 years ago
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Mention the significance of dams and irrigation canals? ​
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<u>Significance</u><u> </u><u>of</u><u> </u><u>dams</u><u> </u><u>and</u><u> </u><u>canals</u><u> </u><u>are</u><u> </u><u>:</u><u>-</u><u> </u>

  • Water is stored in dams that are built across rivers. The water is then supplied to nearby towns and cities through pipelines

  • Water for agricultural purposes is supplied through a system of irrigation canals

<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>~</em>

3 0
3 years ago
A stiff outer layer that helps the cell hold its rigid shape. Can be made
nevsk [136]
I just got this question and it was lipids sorry if i’m wrong
8 0
3 years ago
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