Let the bigger no. be X and the smaller no. be Y
X-Y=48
7-3=4
48÷4=12
X=12×7=84
Y=12×3=36
Step-by-step explanation:
it filled up half the circle (up to the center point) - if we had a full circle. but a little bit is cut off (below AB).
what we see is that the shaded area is the sum of the area of the triangle AOB and 2 equally sized circle segment areas left and right of AOB.
since we are dealing with a half-circle, we have 180° in total. 120° are taken by AOB, so, that leaves us with 180-120 = 60° for both circle segments (so, one has an angle of 30°).
and 2×30° = 1×60°, so we can calculate the area of one 60° segment instead of two 30° segments.
AOB is an isoceles triangle (the legs are equally long, and therefore also the 2 side angles are equal).
the area of this triangle AOB is
1/2 × a × b × sin(C) = 1/2 × 3 × 3 × sin(120) =
= 3.897114317... m²
a circle segment area of 60° is 60/360 = 1/6 of the full circle area (as a full circle = 360°).
so, it's area is
pi×r² × 1/6 = pi×3²/6 = pi×3/2 = 4.71238898... m²
so, the total area of the shaded area is
3.897114317... m² + 4.71238898... m² =
= 8.609503297... m²
Answer:
12) A ( 9, 11, 13, 15)
13) A ( o , a)
14) A (b ∈ ( a, b, c, d, e, f))
15) C ( -364)
16) D (-1°C)
17) B (Negative)
18) C (26 feet)
19) B (7)
Step-by-step explanation:
12) All of these are odd numbers greater than 7
13) These are the only vowels in "MONDAY"
14) Point B cannot belong in a set that already has B
15) -9876 + 9512 = -364
16) 4 - 5 = -1
17) ex: -2 + (-2) = -4
18) -20 + 12 - 18 = -26
19) 3(5) + 4(-2) = 15 - 8 = 7
-Chetan K
Answer:
Step-by-step explanation:
4 cups of J for every 7 cups of soda 4:7
21 cups of soda will take 12 cups of J
If you take the 7 and multiply by 3 you get the 21.
So you will need to multiply the 4 by the 3 to get the 12. You need to keep everything in proportion.
4:7 same as 12:21
4x - 3y + 20 = 0....4x - 3y = -21
4x - 3y = -21.....multiply by -2
5x - 6y = -25
----------------
-8x + 6y = 42 (result of multiplying by -2)
5x - 6y = -25
---------------add
-3x = 17
x = -17/3
this system of equations has 1 solution
