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3 years ago

Worked with radium to learn about radioactive elements.

Chemistry

1 answer:

Marysya12 [62]3 years ago

6 0

Answer:

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Unscramble the word. Lncsuoicno

pickupchik [31]

The word can be conclusion, but it can't be if the ''L'' is capitalized

6 0

3 years ago

- Scientists are studying the effects that melting

KATRIN_1 [288]

Answer: As sea levels rise, coastal communities will lose land and possibly see damages in infrastructure if the levels rise high enough

7 0

3 years ago

Write the combustion product of butane in excess<br> oxygen.

Leto [7]

Answer:

The name of the products are CO2 = carbon dioxide and H2O = water. The type of reaction is a combustion reaction.

Explanation:

8 0

3 years ago

Read 2 more answers

How many grams of HNO3 are produced when 60.0 g of NO2 completely reacts?

olganol [36]

<h3>Answer:</h3>

54.756 g

<h3>Explanation:</h3>

Assuming the equation for the reaction in question;

3NO₂(g) + H₂O(l) → 2HNO₃(aq) + NO(g)

We are given;

Mass of NO₂ as 60.0 g

We are required to calculate the mass of HNO₃ produced

We can calculate the mass of HNO₃ produced using the following simple steps;

<h3>Step 1: Calculate the moles of NO₂</h3>

Moles = Mass ÷ Molar mass

Molar mass of NO₂ = 46.01 g/mol

Therefore;

Moles of NO₂ = 60.0 g ÷ 46.01 g/mol

= 1.304 moles

<h3>Step 2: Calculate the moles of HNO₃ produced </h3>

From the equation, 3 moles of NO₂ reacted to produce 2 mole of HNO₃

Therefore, the mole ratio of NO₂ to HNO₃ is 3 : 2

Thus;

Moles of HNO₃ = Moles of NO₂ × 2/3

= 1.304 moles × 2/3

= 0.869 Moles

<h3>Step 3: Calculate the mass of HNO₃</h3>

Mass = Moles × Molar mass

Molar mass of HNO₃ = 63.01 g/mol

Therefore;

Mass = 0.869 moles × 63.01 g/mol

= 54.756 g

Thus, the mass of HNO₃ produced is 54.756 g

3 0

3 years ago

The hydrogen atom is not actually electronegative enough to form bonds to xenon. were the xenon-hydrogen bond to exist, what wou

Marat540 [252]

Answer : The structure of $XeH_4$ will be square-planar.

Explanation :

In the given molecule $XeH_4$ , 'Xe' is the central atom and 'H' is the terminal atom.

Xenon has 8 valence electrons and hydrogen has 1 valence electron. Therefore, the total number of valence electrons are 8 + 4(1) = 12 electrons.

The number of electrons used in Xe-H bonding = 8 electrons

The remaining electrons which are used as lone pair on central atom (Xe) = 12 - 8 = 4 electrons

There are 4 bonding pairs and 2 lone pairs of electrons, they will be arranged in the octahedral arrangement around the central atom with 2 lone pairs of electrons on central atom. The lone pairs are arranged linearly across the central atom. The resulting structure will be square-planar.

The structure of $XeH_4$ is shown below.

5 0

3 years ago