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3 years ago

Write the combustion product of butane in excess oxygen.

Chemistry

2 answers:

Leto [7]3 years ago

8 0

Answer:

The name of the products are CO2 = carbon dioxide and H2O = water. The type of reaction is a combustion reaction.

Explanation:

yulyashka [42]3 years ago

7 0

Answer:

carbon di oxide and water

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2 years ago

A mysterious compoud with the chemical formula MX (Ksp 1.27x10-36) is present in two different solutions. What is its molar solu

qwelly [4]

<u>Answer:</u> The molar solubility of MX is $2.54\times 10^{-36}M$

<u>Explanation:</u>

We are given:

$K_{sp}(MX)=1.27\times 10^{-36}$

The chemical equation for the ionization of MX follows:

$MX\rightleftharpoons M^+(aq.)+X^-(aq.)$

S S

The expression of $K_{sp}$ for above equation is:

$K_{sp}=S\times S$ ......(1)

The chemical equation for the ionization of $M_2SO_4$ follows:

$M_2SO_4\rightleftharpoons 2M^+(aq.)+SO_4^{2-}(aq.)$

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Total concentration of cation from both the equation is:

$[M^+]=0.5+S$

As, $K_{sp}(MX)$ , so S is also very very less than 1 and can be easily neglected.

So, $[M^+]=0.5M$

Putting values in equation 1, we get:

$1.27\times 10^{-36}=0.5\times S\\\\S=2.54\times 10^{-36}M$

Hence, the molar solubility of MX is $2.54\times 10^{-36}M$

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