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Kryger [21]
3 years ago
8

Where does wave reflection occur?

Physics
2 answers:
alisha [4.7K]3 years ago
7 0
Wave reflection occurs when waves reflect or rebound off of a surface. This is like an echo because the sound waves are reflected from a distant surface 
Galina-37 [17]3 years ago
3 0

Answer:

- at boundaries between two different media

Explanation:

Reflection is one phenomenon that occurs with waves. Reflection can occur when a wave meets the boundary between two different media: when this happens, the wave bounces back into the first media, but changing direction.

In fact, there is a precise relationship between the original direction of the wave and its final direction: calling "angle of incidence" the angle between the original direction and the normal to the surface, and "angle of reflection" the angle between the final direction and the normal to the surface, we have that

angle of reflection = angle of incidence

and this is called "law of reflection".

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A closed pipe and an open pipe have their first overtones identical in frequency. their lengths are in the ratio?
yuradex [85]
You should mention that sound waves are generated in identical conditions i.e the speed of sound is same in the two experiments. 
In that case the ratio is
2v/2L1 :  3v/4L2 = 4L2 : 3L1 .
5 0
3 years ago
6. The potential energy of a freely falling object decreases
lilavasa [31]

Answer:

Explanation:

As the potential energy of the freely falling object decreases, its kinetic energy increases on account of an increase in its velocity. ... Thus, the law of conservation of energy is not violated.

7 0
3 years ago
HELP<br> as shown in the diagram, points p,q, and r are located near a positively charged object.
tester [92]
I can’t open or look at the image
6 0
3 years ago
state position nature and size of an image when an object placed at an distance equal to its focal length of rear view in vehicl
maksim [4K]

Answer:

The position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be

1) Position: Behind the mirror

2) Nature: Virtual

3) Size: Smaller than the object

Explanation:

Due to the nature and use of rear view mirrors, which are meant to enable the front facing driver visualize a wide area of the back portion of the vehicle, such that the images of the object will always remain smaller than the object, require a convex image

The image size, location, nature and orientation of an object placed in front of a convex mirror is diminished, behind the mirror of the upright, virtual, and upright

Therefore, the position nature and size of an image when an object placed at a distance equal to its focal length of rear view mirrors in vehicle will be

Position: Behind the mirror

Nature: Virtual

Size: Smaller than the object.

5 0
3 years ago
Unpolarized light with intensity 370 W/m2 passes first through a polarizing filter with its axis vertical, then through a second
vampirchik [111]

To solve this problem it is necessary to apply the concepts given by Malus regarding the Intensity of light.

From the law of Malus intensity can be defined as

I' = \frac{I_0}{2} cos^2 \theta

Where

\theta =Angle From vertical of the axis of the polarizing filter

I_0 = Intensity of the unpolarized light

The expression for the intensity of the light after passing through the first filter is given by

I = \frac{I_0}{2}

Replacing we have that

I = \frac{370}{2}

I = 185W/m^2

Re-arrange the equation,

I'= \frac{I_0}{2}cos^2\theta

Re-arrange to find \theta

cos^2\theta = \frac{2I'}{I_0}

cos^2\theta = \frac{2*138}{370}

\theta = cos^{-1}(\sqrt{\frac{2*138}{370}})

\theta = 0.5282rad

\theta = 30.27\°

The value of the angle from vertical of the axis of the second polarizing filter is equal to 30.2°

4 0
3 years ago
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