Answer:
(2, -3)
Step-by-step explanation:
Apparently, the equations are supposed to be ...
The solution for x can be found by subtracting the second equation from the first:
(4x +y) -(3x +y) = (5) -(3)
x = 2 . . . . . . . matches the second answer choice
Y can be found from either equation:
y = 5 - 4x . . . . . subtract 4x from the first equation
y = 5 -4(2) = -3
The solution is (x, y) = (2, -3).
Answer:
D
Step-by-step explanation:
i just took a test with that question
The correct answer to this question is <span>d.) integral from 1 to 2 of (2/(x+1))
</span>To solve this:
Since Δx = 1/n.
lim (n→∞) Δx [1/(1+Δx) + 1/(1+2Δx)+ ... + 1/(1+nΔx)]
= lim (n→∞) Σ(k = 1 to n) [1/(1 + kΔx)] Δx.
x <---> a + kΔx
a = 0, then b = 1, so that Δx = (b - a)/n = 1/n
Since (1 + kΔx) combination, a = 1 so that b = 2.
Then, f(1 + kΔx) <-----> f(x) ==> f(x) = 1/x.
This sum represents the integral
∫(x = 1 to 2) (1/x) dx, so the correct answer is <span>d.) integral from 1 to 2 of (2/(x+1))
Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.
</span>
After 2 hours there is 12 bacteria present in the sample
The area of the parallelogram spanned by the given vectors is equal to the magnitude of their cross product.
(i + j + k) × (-2i + 3j + k)
= -2 (i × i) - 2 (j × i) - 2 (k × i)
… + 3 (i × j) + 3 (j × j) + 3 (k × j)
… + (i × k) + (j × k) + (k × k)
= - 2 (j × i) - 2 (k × i) + 3 (i × j) + 3 (k × j) + (i × k) + (j × k)
= 2 (i × j) - 2 (k × i) + 3 (i × j) - 3 (j × k) - (k × i) + (j × k)
= 5 (i × j) - 3 (k × i) - 2 (j × k)
= 5 k - 3 j - 2 i
Then the area of the parallelogram is
||-2 i - 3 j + 5 k|| = √((-2)² + (-3)² + 5²) = √38
