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Damm [24]
3 years ago
10

Can plants stop soil erosion

Chemistry
1 answer:
motikmotik3 years ago
4 0

Answer:

yes. they can block the wind which causes top soil erosion and they also soak up some the water in the soil

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Here’s another one guys please help.
ch4aika [34]

Answer:

Explanation:

i think B im not sure

3 0
3 years ago
What will be the new volume of a 250 mL sample of gas at 300 K and 1 atm if heated to 350 K at 1 atm?
AlekseyPX

The   new volume of a 250  Ml   sample of gas at 300k  and  1atm  if  heated to 350 k  at  1 atm  is  291.67  Ml



<u>calculation</u>

This  is  solved  using  the  Charles  law formula  since the  pressure  is constant.

that is V1/T1 = V2/T2  where,

V1 =250 ml

T1=300  K

V2=?

T2= 350 k


by making V2 the subject   of  the formula  by  multiplying  both side by T2

V2= T2V1/T1

V2= (350 K x 250 ml) / 300K =291.67 Ml


5 0
3 years ago
Is there a way u could see if the element is acid,base or salt in the periodic table?​
Vsevolod [243]

Answer:

OK i see

Explanation:

5 0
2 years ago
Write packing efficiency of fcc ,BCC, SCC and formula also . ?​
Minchanka [31]

❖ <u>Packing Efficiency</u> ❖

➪ The percentage of total space occupied by particles is called <u>packing efficiency</u>.

\\ \qquad{\rule{200pt}{3pt}}

\bigstar \boxed{ \sf \:  \bigg(Packing \; effeciency = \dfrac{Total \; value \; of \; sphere}{Volume \; of \; unit \; cell} \times 100 \bigg)}

❖ Packing efficiency of simple cubic structure (SCC).❖

\rm \: {Let \: } \bf{r } \: \rm{ be  \: the \:  radius  \: of  \: a \:  sphere  }\:  \\ \rm and \: \bf{a} \:  \rm {be \:  the \:  edge \:  of  \: unit \:  cell.} \\  \\  \;  \bigstar \boxed{ \sf{Volume_{(sphere)} = \dfrac{4}{3} \pi r^3}} \bigstar

❒ Since, simple cubic unit cell contain 1 atom (sphere). So, the total volume of sphere will be :

:  : \implies \sf \: 1 \times \dfrac{4}{3}\pi r^3 = \dfrac{4}{3}\pi r^3

  • Volume of unit cell = a³

  • Volume of unit cell = (2r)³

  • Volume of unit cell = 8r³

❒ <u>Now, we know that</u>,❒

\bigstar \boxed{ \sf \:  \bigg(Packing \; effeciency = \dfrac{Total \; value \; of \; sphere}{Volume \; of \; unit \; cell} \times 100 \bigg)}

➪ Substituting the known values in the formula, we get the following results:

:  : \implies \rm \: {\dfrac{\dfrac{4}{3}\pi r^3}{8r^3} \times 100} \\ \\ :  : \implies   \dfrac{\pi}{6} \times 100 \\\\\   :  : \implies \bf {52.4 \%}

❒ Hence, the packing efficiency of simple cubic structure is 52.4%.

\\ \qquad{\rule{200pt}{3pt}}

➪ Packing efficiency of cubic close packing (SCC)/face centred cubic structure (FCC).

\rm \: {Let \: } \bf{r } \: \rm{ be  \: the \:  radius  \: of  \: a \:  sphere  }\:  \\ \rm and \: \bf{a} \:  \rm {be \:  the \:  edge \:  of  \: unit \:  cell.} \\  \\  \;  \bigstar \boxed{ \sf{Volume_{(sphere)} = \dfrac{4}{3} \pi r^3}} \bigstar

❒ Since, simple cubic unit cell contain 2 atom (sphere). So, the total volume of sphere will be:

: : \implies \rm 4 \times \dfrac{4}{3}\pi r^3 = \dfrac{16}{3}\pi r^3

  • Volume of unit cell = a³

Volume of unit cell = (2√2r)³

Volume of unit cell = 16√2r³

❒ <u>Now, we know that</u>,❒

\bigstar \boxed{ \sf \:  \bigg(Packing \; effeciency = \dfrac{Total \; value \; of \; sphere}{Volume \; of \; unit \; cell} \times 100 \bigg)}

➪Substituting the known values in the formula, we get the following results:

:   : \implies \rm {\dfrac{\dfrac{16}{3}\pi r^3}{16\sqrt{2}r^3} \times 100 }\\\\  \implies \rm \dfrac{\pi}{3\sqrt{2}} \times 100 \\\\\  \implies\bf52.4 \%

❖ Hence, the packing efficiency of face centred cubic structure is 74%.

\\ \qquad{\rule{200pt}{3pt}}

❖ Packing efficiency of body cubic structure (BCC).

\rm \: {Let \: } \bf{r } \: \rm{ be  \: the \:  radius  \: of  \: a \:  sphere  }\:  \\ \rm and \: \bf{a} \:  \rm {be \:  the \:  edge \:  of  \: unit \:  cell.} \\  \\  \;  \bigstar \boxed{ \sf{Volume_{(sphere)} = \dfrac{4}{3} \pi r^3}} \bigstar

❒ Since, simple cubic unit cell contain 2 atom (sphere). So, the total volume of sphere will be:

: : \implies  \rm \: 2 \times \dfrac{4}{3}\pi r^3 = \dfrac{8}{3}\pi r^3

  • Volume of unit cell = a³

Volume of unit cell = (4r/√3)³

Volume of unit cell = 64r³/3√3

❒ <u>Now, we know that</u>,❒

\bigstar \boxed{ \sf \:  \bigg(Packing \; effeciency = \dfrac{Total \; value \; of \; sphere}{Volume \; of \; unit \; cell} \times 100 \bigg)}

➪Substituting the known values in the formula, we get the following results:

: : \implies \rm {\dfrac{\dfrac{8}{3}\pi r^3}{\dfrac{64r^3}{3\sqrt{3}}} \times 100} \\\\  \implies \dfrac{3\pi}{8} \times 100 \\\ \\  \bf  \implies \: 68 \%

❒ Hence, the packing efficiency of body centred cubic structure is 68%.

\\ \qquad{\rule{200pt}{3pt}}

6 0
2 years ago
First correct will get brainliest, thank you!
Arlecino [84]

Answer:

well what's the question? we can't see it

3 0
3 years ago
Read 2 more answers
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