The combustion reaction of propane would be expressed as:
C3H8 + 5O2 = 3CO2 + 4H2O
To determine the mass of water that is produced from the given amount of propane, we use the mass of propane and the relation of the substances from the balanced reaction. We do as follows:
moles propane = 22 g C3H8 ( 1 mol / 44.1 g ) = 0.50 mol C3H8
moles H2O = 0.50 mol C3H8 ( 4 mol H2O / 1 mol C3H8) = 2 mol H2O
mass H2O = 2 mol H2O ( 18.02 g / 1 mol ) = 36.04 g H2O
Therefore, the mass of water that is produced from 22 grams of propane would be 36.04 g.
Answer:
In the forward direction and releases carbondioxide gas from backside.
Explanation:
In the forward direction and the carbondioxide gas which is a waste material is removed from the engine at the back. The chemical energy of fuel is converted into mechanical energy with the help of engine which able the car to move in the forward direction so engine is the key component that is responsible for the movement of car.
Kinetic energy is 1/2m*v^2
They already halved the mass for you and they already squared the velocity for you. I’m unsure why you’re even asking this question. It’s simple multiplication at this point.
(27.5kg)*(4m^2/s^2) = 110 Jules