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fgiga [73]
3 years ago
6

Ashley determines the density, mass, and volume of a sample of liquid water. She removes part of the sample and repeats her meas

urements with the remaining water. Which of the following properties should have the same value for both of her measurements?
○All of the above
○Density
○Mass
○Volume​
Chemistry
1 answer:
Paul [167]3 years ago
3 0

Answer:

Only thing that should hold constant is the Density of the water

Explanation:

Since you are removing some of the water, the Mass and Volume will decrease.

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creativ13 [48]

Answer:

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Explanation:

<h3>Removing Energy: Removing energy will cause the particles in a liquid to begin locking into place. A. Boiling and Evaporation: Evaporation is the change of a substance from a liquid to a gas. Boiling is the change of a liquid to a vapor, or gas, throughout the liquid.</h3>

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3 years ago
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a 1.642 g sample of calcium bromide is dissolved in enough water to give 469.1 mL of solution what is the bromide ion concentrat
aleksklad [387]

The bromide concentration in this solution of calcium bromide dissolved in enough water to give 469.1 mL is 1.75 × 10-⁵M.

<h3>How to calculate concentration?</h3>

The concentration of a solution can be calculated by dividing the number of moles of the substance by its volume.

No of moles of calcium bromide is calculated as follows:

moles = 1.642 ÷ 199.89 = 8.215 × 10-³moles

Molarity = 8.215 × 10-³moles ÷ 469.1mL = 1.75 × 10-⁵M

Therefore, the bromide concentration in this solution of calcium bromide dissolved in enough water to give 469.1 mL is 1.75 × 10-⁵M.

Learn more about concentration at: brainly.com/question/10725862

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4 0
2 years ago
What is the final concentration of cl- ion when 250 ml of 0.20 m cacl2 solution is mixed with 250 ml of 0.40 m kcl solution? (as
serious [3.7K]

CaCl2 and KCl are both salts which dissociate in water when dissolved. Assuming that the dissolution of the two salts are 100 percent, the half reactions are:

<span>CaCl2 ---> Ca2+  +  2 Cl-</span>

KCl ---> K+ + Cl-

Therefore the total Cl- ion concentration would be coming from both salts. First, we calculate the Cl- from each salt by using stoichiometric ratio:

Cl- from CaCl2 = (0.2 moles CaCl2/ L) (0.25 L) (2 moles Cl / 1 mole CaCl2)

Cl- from CaCl2 = 0.1 moles

 

Cl- from KCl = (0.4 moles KCl/ L) (0.25 L) (1 mole Cl / 1 mole KCl)

Cl- from KCl = 0.1 moles

 

Therefore the final concentration of Cl- in the solution mixture is:

Cl- = (0.1 moles + 0.1 moles) / (0.25 L + 0.25 L)

Cl- = 0.2 moles / 0.5 moles

<span>Cl- = 0.4 moles             (ANSWER)</span>

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