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3 years ago

A tennis ball with a speed of 25.9 m/s is moving perpendicular to a wall. After striking the wall,

Physics

1 answer:

mihalych1998 [28]3 years ago

6 0

Answer:

$-3550.1 m/s^2$

Explanation:

The initial velocity of the ball is

u = +25.9 m/s (towards the wall)

while the final velocity of the ball is

v = -21.3157 m/s (away from the wall)

The time taken for the change in velocity to occur is

t = 0.0133 s

The acceleration can be calculated as the change in velocity divided by the time taken:

$a=\frac{v-u}{t}$

Substituting the numbers, we find:

$a=\frac{-21.3157-25.9}{0.0133}=-3550.1 m/s^2$

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1) A net force of 75.5 N is applied horizontally to slide a 225 kg crate across the floor.

dimulka [17.4K]

Answer:

The acceleration of the crate is $0.3356\,\frac{m}{s^2}$

Explanation:

Recall the formula that relates force,mass and acceleration from newton's second law;

$F=m\,a$

Then in our case, we know the force applied and we know the mass of the crate, so we can solve for the acceleration as shown below:

$F=m\,a\\75.5\,N=225\,\,kg\,\,a\\a=\frac{75.5}{225} \,\frac{m}{s^2} \\a=0.3356\,\,\frac{m}{s^2}$

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3 years ago

Which best describes the relationship between humidity and air pressure?

spayn [35]

Answer:<span>Humid air is lighter, so it has lower pressure.

The reason is the molecules of water are H2O, whose molar mass is 18 g/mol.

These molecules displaces molecules of N2 and O2, whose molar masses are:

N2: 2*14g/mol = 28 g/mol, and
O2: 2*16g/mol = 32 g/mol.

Then molecules of 28g/mol and 32 g/mol are being replaced with molecules of 18g/mol, leading to a lower weight of the same volume of air, which results in lower pressure.
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5 0

3 years ago

Read 2 more answers

The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz. Find the possible range of wavelengths in ai

taurus [48]

Answer:

The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

Explanation:

Given that,

The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.

The speed of sound in air is 343 m/s.

To find,

The wavelength range for the corresponding frequency.

Solution,

The speed of sound is given by the following relation as :

$v=f_1\lambda_1$

Wavelength for f = 45 Hz is,

$\lambda_1=\dfrac{v}{f_1}$

$\lambda_1=\dfrac{343}{45}=7.62\ m$

Wavelength for f = 375 Hz is,

$\lambda_2=\dfrac{v}{f_2}$

$\lambda_2=\dfrac{343}{375}=0.914\ m/s$

So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.

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3 years ago

If you see ##### in a cell, you should

Sveta_85 [38]

Answer:

it's D. Make the column wider

Explanation:

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3 years ago

Cual es el deporte que le da fortaleza y flexibilidad al cuerpo

AlexFokin [52]

Answer:

Aesthetic sports

Explanation:

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In aesthetic sports like gymnastics, swimming, and figure skaters, dynamic and proactive flexibility is required.

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3 years ago