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3 years ago

A tennis ball with a speed of 25.9 m/s is moving perpendicular to a wall. After striking the wall,

Physics

1 answer:

mihalych1998 [28]3 years ago

6 0

Answer:

$-3550.1 m/s^2$

Explanation:

The initial velocity of the ball is

u = +25.9 m/s (towards the wall)

while the final velocity of the ball is

v = -21.3157 m/s (away from the wall)

The time taken for the change in velocity to occur is

t = 0.0133 s

The acceleration can be calculated as the change in velocity divided by the time taken:

$a=\frac{v-u}{t}$

Substituting the numbers, we find:

$a=\frac{-21.3157-25.9}{0.0133}=-3550.1 m/s^2$

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A rock is thrown from the edge of the top of a 51 m tall building at some unknown angle above the horizontal. The rock strikes t

Xelga [282]

Answer:

The speed of projection is 34 m/s.

Explanation:

Height of building, h = 51 m

horizontal distance, d = 74 m

time, t = 8 s

Let the angle is A and the speed is u.

d = u cos A x t

74 = u cos A x 8

u cos A = 9.25 .... (1)

Use second equation of motion

$h = u sin A t - 0.5 gt^2\\\\-51 = u sinA \times 8 - 0.5\times 9.8\times8\times 8\\\\u sin A = 32.8 .... (2)$

Squaring and adding both the equations

$u^2 = 9.25^2 + 32.8^2 \\\\u = 34 m/s$

8 0

3 years ago

A 2.0-kg pistol fires a 1.0-g bullet with a muzzle speed of 1000 m/s. The bullet then strikes a 10-kg wooden block resting on a

Andreyy89

Answer:

1000 N

Explanation:

An impulse results in a change of momentum

FΔt = mΔv

F = 0.001 kg(1000 - 0) m/s / 0.001 s = 1000 N

4 0

3 years ago

A block rides on a piston that is moving vertically with simple harmonic motion. (a) If the SHM has period 2.68 s, at what ampli

fredd [130]

Answer:

Part a)

$A = 1.78 m$

Part b)

$f = 2 rev/s$

Explanation:

Part A)

As we know that time period of the motion is given as

$T = 2.68 s$

so we have

$\omega = \frac{2\pi}{T}$

$\omega = \frac{2\pi}{2.68}$

$\omega = 2.34 rad/s$

now at the point of maximum amplitude the force equation when Normal force is about to zero is given as

$mg = m\omega^2 A$

so we have

$A = \frac{g}{\omega^2}$

$A = \frac{9.81}{2.34^2}$

$A = 1.78 m$

Part b)

Now if the amplitude of the SHM is 6.23 cm

and now at this amplitude if object will lose the contact then in that case again we have

$mg = m\omega^2 A$

$g = \omega^2 (0.0623)$

$\omega = 12.5 rad/s$

so now we have

$2\pi f = 12.5$

$f = 2 rev/s$

3 0

3 years ago

A wire carries current in the plane of this screen toward the top of the screen. The wire experiences a magnetic force toward th

GenaCL600 [577]

Answer:

The direction of the magnetic field causing this force is

In the plane of the screen and towards the bottom of the egde

Explanation:

This is by applying Fleming s right hand rule which explains that

When a conductor such as a wire attached to a circuit moves through a magnetic field, an electric current is induced in the wire due to Faraday's law of induction. The current in the wire can have two possible directions. Fleming's right-hand rule gives which direction the current flows.

The right hand is held with the thumb, index finger and middle finger mutually perpendicular to each other (at right angles), as shown in the diagram.[1]

The thumb is pointed in the direction of the motion of the conductor relative to the magnetic field.

The first finger is pointed in the direction of the magnetic field. (north to south)

Then the second finger represents the direction of the induced or generated current within the conductor (from the terminal with lower electric potential to the terminal with higher electric potential, as in a voltage source)

7 0

3 years ago

True or false: the energy that is related to moving parts is called electrical energy

NemiM [27]

False, that would be kinetic energy.

3 0

3 years ago