Answer: bismuth and nitrogen, because they have the same number of valence electrons
Explanation:
Elements are distributed in groups and periods in a periodic table.
Elements that belong to same groups will show similar chemical properties because they have same number of valence electrons.
The number of valence electrons in Bismuth and nitrogen are 5 and thus thus they will show similar chemical properties and thus belong to the same group.
The atomic masses of elements in a group will differ drastically.
The group number has got nothing to be the isolation year.
Thus bismuth and nitrogen belong to same group because they have the same number of valence electrons
Answer: Mars
Explanation:
Mars is a planet similar to the earth which the rest can't sustain life either because it's too hot or cold or too much gas maybe even toxic acid.
Answer:
a)![E=50.53\times 10^{6}\ N/C](https://tex.z-dn.net/?f=E%3D50.53%5Ctimes%2010%5E%7B6%7D%5C%20N%2FC)
The direction will be negative direction.
b)
The direction will be positive direction.
Explanation:
Given that
q1 = +7.7 µC is at x1 = +3.1 cm
q2 = -19 µC is at x2 = +8.9 cm
We know that electric filed due to a charge given as
![E=K\dfrac{q}{r^2}](https://tex.z-dn.net/?f=E%3DK%5Cdfrac%7Bq%7D%7Br%5E2%7D)
![E_1=K\dfrac{q_1}{r_1^2}](https://tex.z-dn.net/?f=E_1%3DK%5Cdfrac%7Bq_1%7D%7Br_1%5E2%7D)
![E_2=K\dfrac{q_2}{r_2^2}](https://tex.z-dn.net/?f=E_2%3DK%5Cdfrac%7Bq_2%7D%7Br_2%5E2%7D)
Now by putting the va;ues
a)
![E_1=9\times 10^9\times \dfrac{7.7\times 10^{-6}}{0.031^2}\ N/C](https://tex.z-dn.net/?f=E_1%3D9%5Ctimes%2010%5E9%5Ctimes%20%5Cdfrac%7B7.7%5Ctimes%2010%5E%7B-6%7D%7D%7B0.031%5E2%7D%5C%20N%2FC)
![E_1=72.11\times 10^{6}\ N/C](https://tex.z-dn.net/?f=E_1%3D72.11%5Ctimes%2010%5E%7B6%7D%5C%20N%2FC)
![E_2=9\times 10^9\times \dfrac{19\times 10^{-6}}{0.089^2}\ N/C](https://tex.z-dn.net/?f=E_2%3D9%5Ctimes%2010%5E9%5Ctimes%20%5Cdfrac%7B19%5Ctimes%2010%5E%7B-6%7D%7D%7B0.089%5E2%7D%5C%20N%2FC)
![E_2=21.58\times 10^{6}\ N/C](https://tex.z-dn.net/?f=E_2%3D21.58%5Ctimes%2010%5E%7B6%7D%5C%20N%2FC)
The net electric field
![E=E_1-E_2](https://tex.z-dn.net/?f=E%3DE_1-E_2)
![E=50.53\times 10^{6}\ N/C](https://tex.z-dn.net/?f=E%3D50.53%5Ctimes%2010%5E%7B6%7D%5C%20N%2FC)
The direction will be negative direction.
As we know that electric filed line emerge from positive charge and concentrated at negative charge.
b)
Now
distance for charge 1 will become =5.5 - 3.1 = 2.4 cm
distance for charge 2 will become =8.9-5.5 = 3.4 cm
![E_1=9\times 10^9\times \dfrac{7.7\times 10^{-6}}{0.024^2}\ N/C](https://tex.z-dn.net/?f=E_1%3D9%5Ctimes%2010%5E9%5Ctimes%20%5Cdfrac%7B7.7%5Ctimes%2010%5E%7B-6%7D%7D%7B0.024%5E2%7D%5C%20N%2FC)
![E_1=120.3\times 10^{6}\ N/C](https://tex.z-dn.net/?f=E_1%3D120.3%5Ctimes%2010%5E%7B6%7D%5C%20N%2FC)
![E_2=9\times 10^9\times \dfrac{19\times 10^{-6}}{0.034^2}\ N/C](https://tex.z-dn.net/?f=E_2%3D9%5Ctimes%2010%5E9%5Ctimes%20%5Cdfrac%7B19%5Ctimes%2010%5E%7B-6%7D%7D%7B0.034%5E2%7D%5C%20N%2FC)
![E_2=147.92\times 10^{6}\ N/C](https://tex.z-dn.net/?f=E_2%3D147.92%5Ctimes%2010%5E%7B6%7D%5C%20N%2FC)
The net electric field
![E=E_1+E_2](https://tex.z-dn.net/?f=E%3DE_1%2BE_2)
![E=268.22\times 10^{6}\ N/C](https://tex.z-dn.net/?f=E%3D268.22%5Ctimes%2010%5E%7B6%7D%5C%20N%2FC)
The direction will be positive direction.