Question

When a charged particle moves at an angle of 25° with respect to a magnetic field, it experiences a magnetic force of magnitude F. At what angle (less than 90°) with respect to this field will this particle, moving at the same speed, experience a magnetic force of magnitude 2F?

Answer 1

Answer:57.7

Explanation:

Force on a moving charge in  a magnetic field is given by

$F=q\times V\times Bsin\theta$

Where F=Force experienced by charge

q=charge of particle

V=velocity of particle

B=magnetic field

F=qVBsin(25)-------1

$2F=qVBsin(\theta )------2$

Divide (1)&(2)

$\frac{1}{2}$=$\frac{sin(25)}{sin(\theta)}$

$Sin(\theta )=2\times sin(25)$

$\theta =57.7 ^{\circ}$