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dybincka [34]
3 years ago
5

When a charged particle moves at an angle of 25° with respect to a magnetic field, it experiences a magnetic force of magnitude

F. At what angle (less than 90°) with respect to this field will this particle, moving at the same speed, experience a magnetic force of magnitude 2F?
Physics
1 answer:
sasho [114]3 years ago
7 0

Answer:57.7

Explanation:

Force on a moving charge in  a magnetic field is given by

F=q\times V\times Bsin\theta

Where F=Force experienced by charge

q=charge of particle

V=velocity of particle

B=magnetic field

F=qVBsin(25)-------1

2F=qVBsin(\theta )------2

Divide (1)&(2)

\frac{1}{2}=\frac{sin(25)}{sin(\theta)}

Sin(\theta )=2\times sin(25)

\theta =57.7 ^{\circ}

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