All categories

3 years ago

A rectangular solid is 5m long, 2m high and 4m wide. The mass of the solid is 300g. Find the density of this solid.

Physics

1 answer:

Over [174]3 years ago

4 0

Answer:

Density = Mass / Volume

Mass = .3 kg

Volume = 2 * 5 * 4 = 40 m^3

Density = .3 g / 40 m^3 = .0075 kg / m^3

1 kg/m^3 = kg * 1000 g / kg / (1 m^3 * (100 cm/m)^3) = 10E-3 gm/cm^3

Density = 7.5 E-3 gm/cm^3

You might be interested in

Two parallel plates having charges of equal magnitude but opposite sign are separated by 11.0 cm. Each plate has a surface charg

VashaNatasha [74]

Two parallel plates having charges of equal magnitude but opposite sign are separated by 11.0 cm. Each plate has a surface charge density of 49.0 nC/m2. A proton is released from rest at the positive plate.

(a) Determine the magnitude of the electric field between the plates from the charge density.

b) Determine the potential difference between the plates.

Answer:

The Electric Field between the two plate is $E = 5.536*10^3 N/C$

The potential difference between the plate is V = $609 \ Volts$

Explanation:

From the we are given that

The separation between the plate is $d = 11.0 cm$

The surface charge density is $\sigma = 49.0 n C/m^2 = 49.0*10^{-9}$

Generally Electric field between the plate is mathematically given as

$E = \frac{\sigma }{\epsilon_0}$

Note that $\epsilon_0$ is the permitivity of free space and its value is $8.85 *10 ^{-12} C^2 /N \cdot m^2$

Now substituting values we have

$E = \frac{49*10^{-9}}{8.85*10^{-12}}$

$5.537*10^3 N/C$

Generally Potential difference between the plate is mathematically given as

$V =Ed$

Where E is the electric field which is $E = 5.536*10^3 N/C$

Substituting value we have

V = $= (5.537*10^3 N/C) (11.0*10^{-2}) =609 V$

3 0

4 years ago

William adds two values, following the rules for using significant figures in computations he should write the sum of theses two

scoundrel [369]

Answer: the same number of decimal places as the least precise value.

Explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

For example: 12.1 + 3.245 = 15.3 as the least precise number 12.1 has one decimal place.

Thus William should write the sum of these two numbers by using the same number of decimal places as the least precise value.

Source: brainly.com/question/1453960

4 0

2 years ago

Using the solar constant, estimate the rate at which the whole Earth receives energy from the Sun. (Hint: Think about the area o

harkovskaia [24]

Answer:

1.475×10²⁴ W

Explanation:

I = Solar constant of the sun = 1362 W/m² (measured using satellites with value 1.3608 ± 0.0005 kW/m² the error is due to fact that solar output is not always constant)

r = Radius of earth = 6371 km = 6371000 m (mean radius)

A = Area of earth = (4/3)×π×r³

=(4/3)×π×6371000³ = 1.083×10²¹ m²

P = I×A

⇒P = 1362×1.083×10²¹

⇒P = 1.475×10²⁴ W

∴ Rate at which the whole Earth receives energy from the Sun is 1.475×10²⁴ W

4 0

3 years ago

Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t

wolverine [178]

Answer:

final velocity = 0.08585m/s

Explanation:

We are taking train cars as our system. In this system no external force is acting. So we can apply the law of conservation of linear momentum.

The law of conservation of linear momentum states that the total linear momentum of a system remains constant if there is no external force acting on the system. That is total linear momentum before = total linear momentum after

total linear momentum before = linear momentum of first train car + linear momentum of second train car

We know that linear momentum = mv

where,

m = mass

v = velocity

thus,

total linear momentum before = m₁v₁ + m₂v₂

m₁ = mass of first train car = 135,000kg

v₁ = velocity of first train car = 0.305m/s

m₂ = mass of first second car = 100,000kg

v₂ = velocity of second train car = −0.210m/s

Note: Momentum is a vector. So while adding momentum we should take account of its direction too. Here since second train car is moving in a direction opposite to that of the first one, we have taken its velocity as negative.

total linear momentum before = m₁v₁ + m₂v₂

= 135,000x0.305 + 100,000x(−0.210)

= 135,000x0.305 - 100,000x0.210

= 20,175 kgm/s

Now we have to find total linear momentum after bumping. After the bumping both the train cars will be moving together with a common velocity(say v).

Therefore, total linear momentum after = mv

m = m₁ + m₂ = 135,000 + 100,000 = 235,000

total linear momentum before = total linear momentum after

235,000v = 20,175

v = $\frac{20,175}{235,000}$

= 0.08585m/s

8 0

3 years ago

Read 2 more answers

A student decides to spend spring break by driving 50 miles due east, then 50 miles 30 degrees south of east, then 50 miles 30 d

PolarNik [594]

Answer:

a. 600 ml, 12

Explanation:

The movement described in the question exhibits that of a polygon. Exhibiting a constant distance and angle with only varying direction until the starting point is reached.

The sum of exterior angles of a polygon = 360 degrees.

Exterior angle of a polygon = (360 ÷ number of sides)

Therefore,

Number of sides = 360 ÷ exterior angle

Exterior angle = 30 degrees

Hence,

Number of sides = 360 ÷ 30 = 12 sides

Since distance traveled of 50 miles is the same for each displacement ;

Total displacement = distance traveled * number of sides

Total displacement = 50 * 12 = 600 miles.

5 0

3 years ago

A rectangular solid is 5m long, 2m high and 4m wide. The mass of the solid is 300g. Find the density of this solid.​

A rectangular solid is 5m long, 2m high and 4m wide. The mass of the solid is 300g. Find the density of this solid.