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erica [24]
3 years ago
15

A rectangular solid is 5m long, 2m high and 4m wide. The mass of the solid is 300g. Find the density of this solid.​

Physics
1 answer:
Over [174]3 years ago
4 0

Answer:

Density = Mass / Volume

Mass = .3 kg

Volume = 2 * 5 * 4 = 40 m^3

Density = .3 g / 40 m^3 = .0075 kg / m^3

1 kg/m^3 = kg * 1000 g / kg / (1 m^3 * (100 cm/m)^3) = 10E-3  gm/cm^3

Density = 7.5 E-3 gm/cm^3

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3 0
3 years ago
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Choose what colors are absorbed when white light hits a red apple. (Pick all that apply.)
astra-53 [7]
A red apple absorbs all colors of visible light except red, so red light
is the only light left to bounce off of the apple toward our eyes. 
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Here's how the various items on the list make out when they hit the apple:

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4 0
3 years ago
An electron passes through a point 2.83 cm 2.83 cm from a long straight wire as it moves at 35.5 % 35.5% of the speed of light p
igor_vitrenko [27]

Answer:

The magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

Explanation:

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For finding the acceleration,

First find the magnetic field due to wire,

  B = \frac{\mu _{o}I }{2\pi r }

Where \mu_{o} = 4\pi   \times 10^{-7}

  B = \frac{4\pi \times 10^{-7}  \times 17.7 }{2\pi (2.83 \times 10^{-2} ) }

  B = 12.50 \times 10^{-5} T

The magnetic force exerted on the electron passing through straight wire,

  F = qvB  

  F = 1.6 \times 10^{-19} \times 0.355 \times 3 \times 10^{8} \times 12.50 \times 10^{-5}

  F = 21.3 \times 10^{-16} N

From the newton's second law

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Where m = mass of electron = 9.1 \times 10^{-31} kg

So acceleration is given by,

   a = \frac{F}{m}

   a = \frac{21.3 \times 10^{-16} }{9.1 \times 10^{-31} }

   a = 2.34 \times 10^{15} \frac{m}{s^{2} }

Therefore, the magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

7 0
3 years ago
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Plz answer brainliest if right!
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