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3 years ago

A wave travels at a constant speed. How does the frequency change if the wavelength increases by a factor of 2?

Physics

2 answers:

Kay [80]3 years ago

8 0

A.The Frequency decreases by a factor of 2.

NARA [144]3 years ago

3 0

Answer : The frequency decreases by a factor of 2.

Explanation :

Given that the wave travels at a constant speed. The speed of the wave is given as :

$v=\nu\times \lambda$

Where

υ is the frequency of the wave

and λ is the wavelength of the wave.

In this case, the speed is constant. So, the relation between the frequency and the wavelength is inverse.

$\nu\propto \dfrac{1}{\lambda}$

If the wavelength increases by a factor of 2, its frequency will decrease by a factor of 2.

Hence, the correct option is (A) " The frequency decreases by a factor of 2 ".

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What is the difference between resistance and resistivity

Crank

Answer:

google it up

Explanation:

it's there

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3 years ago

Read 2 more answers

How many years would it take to reach the planet saturn travelling at 21 thousand miles per hour? enter your answer with 2 decim

Dmitry_Shevchenko [17]

It would take about 4.8 years to travel from earth to Saturn.

<h3>How long would it take?</h3>

We know that speed is expressed as the ratio of distance to time. In this case, we are trying to know ow many years would it take to reach the planet Saturn travelling at 21 thousand miles per hour.

Given that;

Speed = 21 thousand miles per hour

time taken = ???

Distance = 887 million miles

Speed = distance/time

speed * time = distance

time = distance/speed

time = 8.87 * 10^8 miles/2.1 * 10^4 miles per hour

time = 4.22 * 10^4 hours

If 8.766 * 10^3 hours make 1 year

4.22 * 10^4 hours make 4.22 * 10^4 hours * 1 year/8.766 * 10^3

= 4.8 years

Learn more about Saturn:brainly.com/question/12181523

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8 0

1 year ago

Bob is standing at rest. Wendy runs past him at a constant speed of 3.00 m/s. At the instant that Wendy passes him, Bob starts t

77julia77 [94]

Answer:

90 meters

Explanation:

To find the distance in which Bob catches up with Wendy, you first write down the motion equations of both Bob and Wendy.

Wendy has a constant speed, then you have:

$x_1=v_1t$ (1)

Bob has an accelerated motion, then, his equation of motion is:

$x_2=v_2t+\frac{1}{2}at^2$ (2)

v1: constant speed of Wendy = 3.00 m/s

v2: initial speed of Bob = 0 m/s

a: acceleration of Bob = 0.200m/s^2

When Bob catches up with Wendy x1 = x2, then you equal both equations and solve for time t:

$x_1=x_2\\\\v_1t=\frac{1}{2}at^2\\\\t=\frac{2v_1}{a}$

you replace the values of a and v1:

$t=\frac{2(3.00m/s)}{0.200m/s^2}=30 s$

Finally, you replace this value of time either the equation for x1 or the equation for x2, and you calculate the distance:

$x_2=x_1=(3.00m/s)(30s)=90m$

hence, Bob catches up with Wendy for a distance of 90m

3 0

3 years ago

What is the energy of the photon that could cause (a) an electronic transition from then= 4 state to the n 5 state of hydrogen a

Fiesta28 [93]

Answer:

a) $E_photon =0.306 eV$

b) $E_photon =0.166 eV$

Explanation:

The energy of the photon (E) for $n^th$ orbit of the hydrogen atom is given as:

$E_photon = E_o(\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}})$

where,

$E_o$ = 13.6 eV

n = orbit

a) Now for the transition from n = 4 to n = 5

$E_photon =13.6(\frac{1}{4^{2}}-\frac{1}{5^{2}})$

$E_photon =0.306 eV$

b) Now for the transition from n = 5 to n = 6

$E_photon =13.6(\frac{1}{5^{2}}-\frac{1}{6^{2}})$

$E_photon =0.166 eV$

7 0

3 years ago

If a stone with an original velocity was of 0 Is falling from a ledge and takes 8 seconds to hit the ground what is the final ve

Llana [10]

A=(v-u)/t
10=v/8
v=80(unit)

3 0

3 years ago