I would say A not 100℅ thou
Genus’s mastermind hope that helps
Answer:
d = 61.75 m
Explanation:
Given that,
A ball droped from a building.
We need to find how fast is it traveling after falling 3.55 s.
As it is dropped, its initial velocity is equal to 0.
Let d is the distance it covers after falling 3.55 s.
We can use second equation of motion to find d.

Here, u = 0 and a =g

So, it will cover 61.75 m after falling 3.55 seconds.
Answer:
Inverted (displaced downwards)
Explanation:
The pulse becomes INVERTED upon reflecting off the boundary with the wall. That is, an upward-displaced pulse will reflect off the end and return with a downward displacement. This inversion behavior will always be observed when the end of the medium is fixed, like this wall in this instance. This INVERSION BEHAVIOR can also be observed when the medium is connected to another more heavy or more dense medium. And in this case, when the pulse reaches the end of the medium, a portion of the pulse will reflect off the end and return with an inverted displacement. The heavier medium acts like a fixed end to cause the pulse to be inverted.
Summary: a pulse reaching the end of a medium becomes inverted whenever it either:
i. reflects off a fixed end,
ii. is moving in a less dense medium and reflects off a more dense medium.
Answer:
Elastic potential energy, E = 3.26 J
Explanation:
It is given that,
Force constant of the spring, k = 5.2 N/m
Relaxed length of the spring, X = 2.45 m
When the mass is attached to the end of the spring, the vertical length of the spring is, x' = 3.57 m
To find,
The elastic potential energy stored in the spring.
Solution,
The extension in the length of the spring is given by :


x = 1.12 m
The elastic potential energy of the spring is given by :


E = 3.26 J
So, the elastic potential energy stored in the spring is 3.26 joules.