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3 years ago

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A 47 kg mass is moving across a horizontal surface at 8 m/s. What is the force required to bring the mass to a stop in 4.1 secon

ds? (Hint: This is a multi-step calculation and your answer should come out to be negative). Write your answer to one decimal place.

1 answer:

crimeas [40]3 years ago

6 0

Answer:

Force = -91.7 Newton

Explanation:

Given the following data;

Mass = 47 kg

Time = 4.1 seconds

Initial velocity = 8 m/s

Since the object comes to a stop, its final velocity would be equal to zero.

To find the force required to bring it to stop;

First of all, we would determine the acceleration of the object;

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Substituting into the equation;

$a = \frac{0 - 8}{4.1}$

$a = \frac{-8}{4.1}$

Acceleration, a = -1.95 m/s²

Next, we would determine the force required to bring the object to stop;

$Force = mass * acceleration$

$Force = 47 * -1.95$

Force = -91.65 ≈ 91.7 Newton

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