Check the picture below.

so is really just a cylinder with a cone on the side, notice, since the diameter of the base is 4, the radius is half that then.

so we just simply get the volume of the cylinder, and the cone, and sum them up

$\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=2\\
h=6
\end{cases}\implies V=\pi \cdot 2^2\cdot 6\\\\
-------------------------------\\\\
\textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=2\\
h=2
\end{cases}\implies V=\cfrac{\pi \cdot 2^2\cdot 2}{3}\\\\
-------------------------------\\\\
\stackrel{cylinder's~volume}{24\pi }~~+~~\stackrel{cone's~volume}{\cfrac{8\pi }{3}}$

5 0

3 years ago

Read 2 more answers

A b c d thank youuuuuuuuuu

Vesna [10]

Answer:

$\frac{4x}{x-2}+\frac{7}{x-2}$

Step-by-step explanation:

The general rule for add or subtracting fractions is that the fractions must have a common denominator, meaning that the value under the fraction bar must be the same. This rule is also applicable for algebraic fractions.

Therefore, when the question asks "Which of the following can be added without altering any of the fractions?", one should be looking for two fractions with a common denominator. Thus the answer would be the first option, which is the following;

$\frac{4x}{x-2}+\frac{7}{x-2}$

4 0

3 years ago