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3 years ago

Match the term to the correct definition or example.

Chemistry

1 answer:

GaryK [48]3 years ago

3 0

The amount of energy required to remove an electron from an atom. 2 ionization energy

A bond where electrons are shared unequally, resulting in a positively charged end and a negatively charged end of the molecule, 4 polar covalent bond

The tendency of an atom to attract a pair of electrons and bond with another atom; increases from bottom-left toward top-right of the periodic table. 3. Electronegativity

A bond where electrons are shared equally, or polar bonds in the molecule cancel each other out. 5. Non polar covalent bond

Shell or energy level where electrons are found. 1. Orbital

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What is the name of the organization where Chris brown works?

Nitella [24]

Answer: Chris Brown has launched a charity organization called the Symphonic Love Foundation.

Explanation:

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2 years ago

When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6

Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is $3.07\times 10^{-19} J$

Explanation:

Wavelength of the photon emitted = $\lambda =646.3 nm =646.3\times 10^{-9} m$

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

$E=\frac{hc}{\lambda }$

h = Planck's constant = $6.626\tiomes 10^{-34} Js$

c = Speed of the light = $3\times 10^8 m/s$

$E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}$

$E=3.07\times 10^{-19} J$

The energy difference between these 2p and 2s orbitals is $3.07\times 10^{-19} J$

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4 years ago

2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2

Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

$100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}$

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

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3 years ago

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Physical weathering

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3 years ago

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natali 33 [55]

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4 years ago

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