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Ipatiy [6.2K]
3 years ago
12

Which type of mixture can be separated using distillation? A compound with elements of different boiling points Homogeneous mixt

ure with components of different boiling points A compound with elements of similar boiling points Homogeneous mixture with components of similar boiling pointsWhich type of mixture can be separated using distillation? A compound with elements of different boiling points Homogeneous mixture with components of different boiling points A compound with elements of similar boiling points Homogeneous mixture with components of similar boiling points
Chemistry
2 answers:
nalin [4]3 years ago
7 0
<h3>Answer:</h3>

Homogeneous mixture with components of different boiling points

<h3>Explanation:</h3>
  • Distillation is a method of separating miscible mixtures which contain components that have different boiling points.
  • The mixture is heated and the component with the low boiling point evaporates first. It is then condensed in the condenser and the distillate collected using a clean beaker.
  • For example, a miscible solution of ethanol and water can be separated using distillation.
  • Ethanol and water have different boiling points of 78°C and 100°C respectively. Ethanol is distilled out first because it has a low boiling point compared to water.

inessss [21]3 years ago
7 0

Answer:

B

Explanation:

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Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:
Lubov Fominskaja [6]

Answer:

\boxed{3.966 \times 10^{24}\text{ atoms of Ag}}

Explanation:

(a) Balanced equation

Cu + 2AgNO₃ ⟶ Cu(NO₃)₂+ 2Ag

(b) Calculation

You want to convert atoms of Cu to atoms of Ag.

The atomic ratio is ratio is 2 atoms Ag:1 atom Cu

\text{Atoms of Ag} = 19.83 \times 10^{23}\text{atoms Cu} \times \dfrac{\text{2 atoms Ag}}{\text{1 atom Cu}}\\\\= 3.966 \times 10^{24}\text{ atoms of Ag}\\\\\text{The reaction will produce }\boxed{\mathbf{3.966 \times 10^{24}}\textbf{ atoms of Ag}}

4 0
3 years ago
Read 2 more answers
What is the voltage for the nonspontaneous reaction between silver (Ag) and copper (Cu) and their ions?
gayaneshka [121]
For an non spontaneous reaction between silver (Ag) and copper (Cu) and their ions, Cu is the oxidizing agent while Ag+ is the reducing agent,
The following reactions will take place;
Anode Cu = Cu+2 + 2e-   E= +0.34 volts
Cathode; Ag+ + e = Ag    E = +0.80 volts
The net reaction will be Cu + 2Ag+ = Cu+2 + 2Ag
Thus, the voltage will be
  = +0.80 - (+0.34)
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If you start with 10ml of 0.75 m cu(no3)2 how much cu (s) in grams should be recovered in step #7
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<span>0.48 grams. Not a well worded question since it's assuming I know the reactions. But I'll assume that since there's just 1 atom of copper per molecule of Cu(NO3)2, that the reaction will result in 1 atom of copper per molecule of Cu(NO3)2 used. With that in mind, we will have 0.010 l * 0.75 mol/l = 0.0075 moles of copper produced. To convert the amount in moles, multiply by the atomic weight of copper, which is 63.546 g/mol. So 0.0075 mol * 63.546 g/mol = 0.476595 g. Round the results to 2 significant figures, giving 0.48 grams.</span>
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