Answer:
Explanation:
Given that
d= 35 μm ,yield strength = 163 MPa
d= 17 μm ,yield strength = 192 MPa
As we know that relationship between diameter and yield strength


d = diameter
K =Constant

So now by putting the values
d= 35 μm ,yield strength = 163 MPa
------------1
d= 17 μm ,yield strength = 192 MPa
------------2
From equation 1 and 2

K=394.53
By putting the values of K in equation 1


Now when d= 12 μm


Answer:
uranium is classifide as actinide a chemical element atomic number 92 and is a solid at room temperature
<span>oxidizing substance removes electrons from another substance, which are then added to itself, the oxidizing substance becomes “reduced” (more negative). And because it “accepts” electrons .</span>
Use the equation Q = mCT.
Q is the amount of energy in joules.
m is the mass in grams.
C is the specific heat of water (4.184 J/g °C).
T is the change in temperature.
0.700 pints = 331.224 g of water
Q = (331.224 g)(4.184 J/g °C)(100° C - 30° C)
Q = 97,008.885 J
Divide by 1,000 to convert to kilojoules:
97.009 kJ