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Vesna [10]
3 years ago
14

Which of the following compounds will undergo an Sn2 reaction most readily?

Chemistry
1 answer:
Bad White [126]3 years ago
4 0

Answer:

nekwkz8 waxed

Explanation:

snswko1u219ux8w ok qqm see

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Scientists believe that interactions between atoms depend mostly on the arrangement of the outermost electrons in each atom. Thi
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I’m pretty sure it’s in a group (column) of the period table. Hope this helps :)))
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A student decides to dissolve crackers in their soup as fast as possible. After increasing the surface area of the crackers, the
Margarita [4]

Answer:

They can let the cracker sit in the soup for a few minutes

3 0
3 years ago
Determine the specific heat of a 70 g sample of material that absorbed 96 J as it was heated from 293 K to 313 K
Damm [24]

This problem is providing us with the mass (70 g), absorbed heat (96 J) and initial and final temperatures (293 K and 313 K, respectively) so the specific heat of the material is required and found to be 0.0686 J/(g*K) as shown below:

<h3>Calorimetry:</h3>

In chemistry, we can go over calorimetry by writing the following relationship among heat, mass, specific heat and temperature change:

Q=mC(T_f-T_i)

Thus, one can get the specific heat by solving for C in the previous equation:

C=\frac{Q}{m(T_f-T_i)}

Hence, we can plug in the given data to obtain:

C=\frac{96J}{70g(313K-293K)}\\ \\C=0.0686\frac{J}{g*K}

Learn more about calorimetry: brainly.com/question/1407669

5 0
2 years ago
*SCIENCE*
ICE Princess25 [194]

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Their radiation facilitates nuclear fusion in young stars.


7 0
3 years ago
Read 2 more answers
Equal volumes of hydrogen and helium gas are at the same pressure. The atomic mass of helium is four times that of hydrogen. If
OverLord2011 [107]

Answer:

The ratio of the temperature of helium to that of hydrogen gas is 2:1.

Explanation:

Atomic mass of hydrogen = M

Temperature of hydrogen gas =T

Pressure of the hydrogen gas = P

Mass of the hydrogen gas = m

Moles of the hydrogen gas = n=\frac{m}{2M}

Volume of the hydrogen gas = V

Using an ideal gas equation:

PV=nRT=PV=\frac{mRT}{M}...(1)

Temperature of helium gas =T'

Pressure of the helium gas = P'= P

Mass of the helium gas = m' =m

Moles of the helium  gas = n'=\frac{m}{M'}=\frac{m}{4M}

Volume of the helium gas = V' = V

Using an ideal gas equation:

P'V'=n'RT'=\frac{mRT'}{4M}...(2)

Divide (2) by (1)

\frac{P'V'}{PV}=\frac{\frac{mRT'}{4M}}{\frac{mRT}{2M}}

\frac{T'}{T}=\frac{2}{1}

The ratio of the temperature of helium to that of hydrogen gas is 2:1.

7 0
3 years ago
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