A science teacher who was teaching a unit on minerals modeled mineral formation for the class. She heated granular sugar and a v
2 answers:
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Answer:
option C
Explanation:
given,
diameter of circular room = 8 m
rotational velocity of the rider = 45 rev/min
=
=4.712 rad/s
here in this case normal force is equal to centripetal force
N = m r ω²
N = m x 4 x 4.712²
N = 88.83m
frictional force = μ N
= 88.83m x μ
now, for the body to not to slide
gravity force is equal to frictional force
m g = 88.83 m x μ
g = 88.83 x μ
9.8 = 88.83 x μ
μ = 0.11
hence, the correct answer is option C
Answer:
This is about 176 times the weight of the froghopper.
Explanation:
the grasshopper converts kinetic energy into earth gravitational potential energy
u=mgh
u=12*10^-3*9.8*0.7
=8.23*10^-2
using the Work energy principle
equating the kinetic energy to the potential energy
k +U+w=K2+u2
K+0+0=0+U2
k=8.23*10^-2
force exerted by the grasshopper on the round will be given by tis equation
(F-mg)Ycos=k
(F-12*10^-3*9.8)*0.004cos 0=8.23*10^-2
F=20.7N
from newtons third law of motion, action and reaction are equal and opposite
F=-20.7N
comparing the forces by the two bodies
F:mg
-20.7:-12*10^-3*9.8
the magnitude of the force applied by the grasshopper is found to be 176 times the gravitational force
Answer:
A. Object A requires twice the force to stop as Object B.
Explanation:
Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.
Mathematically, it is given by the formula;
<em>Let's assume the following values;</em>
Mass of object B = 10 kg
Mass of object A = 2 * B = 2 * 10 = 20 kg
Acceleration = 5 m/s²
I. To find the force for B;
<em>Force B = 50 Newton</em>
II. To find the force for A;
<em>Force A = 100 Newton</em>
From the calculation, we can deduce that Force A (100 N) is twice or double the value of Force B (50 N).
<em>In conclusion, since object A has twice the mass of object B and both objects are moving at the same speed, object A would require twice the force to stop as Object B.</em>
Answer:
0.86 m
Explanation:
q₁ = magnitude of positive charge = 5 x 10⁻⁶ C
q₂ = magnitude of negative charge = 3 x 10⁻⁶ C
r = distance between the two charges = 0.250 m
d = distance of the location of third charge from negative charge
q = magnitude of charge on third charge
Using equilibrium of electric force on third charge
d = 0.86 m