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3 years ago

Describe the radial velocity curve. What is its shape? What is its amplitude? What is the orbital period?

Chemistry

1 answer:

lutik1710 [3]3 years ago

7 0

Answer:

The radial velocity curve describes how fast a star is moving in its orbit around a center of mass ( m )

Curve amplitude : This is the maximum value of the radial velocity curve

Radial velocity shape ; The shape of Radial velocity curve is parabolic in nature

Orbital period : Orbital period is the time taken by the star to make one complete rotation in its orbit

Explanation:

The radial velocity curve describes how fast a star is moving in its orbit around a center of mass ( m ) while Curve amplitude is the maximum value of the radial velocity curve also The shape of Radial velocity curve is parabolic in nature. and Orbital period is the time taken by the star to make one complete rotation in its orbit

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What is chemsity and what does it have to do with science

MatroZZZ [7]

Chemistry is the study of the composition of matter and the ways in which matter interacts, combines, and changes under certain conditions. Although not as fundamental as physics, chemistry is a very basic and broad science. It helps us explain bodily interactions and natural process (biochemistry), it helps us to manufacture new medications, and true chemistry research will always follow the scientific method.

4 0

3 years ago

At 25 °C, how many dissociated OH– ions are there in 1243 mL of an aqueous solution whose pH is 2.07?

coldgirl [10]

<u>Answer:</u> The number of $OH^-$ ions dissociated are $8.57\times 10^{11}$

<u>Explanation:</u>

We are given:

pH = 2.07

Calculating the value of pOH by using equation, we get:

$2.07+pOH=14\\\\pOH=14-2.07=11.93$

To calculate hydroxide ion concentration, we use the equation to calculate pOH of the solution, which is:

$pOH=-\log[OH^-]$

We are given:

pOH = 11.93

Putting values in above equation, we get:

$11.93=-\log[OH^-]$

$[OH^-]=10^{-11.93}=1.17\times 10^{-12}M$

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of solution = $1.17\times 10^{-12}M$

Volume of solution = 1243 mL = 1.243 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$1.17\times 10^{-12}M=\frac{\text{Moles of }OH^-}{1.243L}\\\\\text{Moles of }OH^-=(1.17\times 10^{-12}mol/L\times 1.243L)=1.424\times 10^{-12}mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, $1.424\times 10^{-12}mol$ number of $OH^-$ will contain = $(1.424\times 10^{-12}\times 6.022\times 10^{23})=8.57\times 10^{11}$ number of ions

Hence, the number of $OH^-$ ions dissociated are $8.57\times 10^{11}$

3 0

3 years ago

How many neutrons does the most common isotope of hydrogen have?

Lorico [155]

Protium - the most common isotope of hydrogen - has no neutrons in its nucleus.

3 0

3 years ago

Balloon has a volume of 600-ml at temperature of 360 K. If the temperature of

Molodets [167]

Answer:

V₂ ≈416.7 mL

Explanation:

This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.

V₁ / T₁ = V₂ / T₂

where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.

The balloon has a volume of 600 milliliters and a temperature of 360 K, but the temperature then drops to 250 K. So,

V₁= 600 mL
T₁= 360 K
T₂= 250 K

Substitute the values into the formula.

600 mL /360 K = V₂ / 250 K

Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.

250 K * 600 mL /360 K = V₂ / 250 K * 250 K

250 K * 600 mL/360 K = V₂

The units of Kelvin cancel, so we are left with the units of mL.

250 * 600 mL/360=V₂
416.666666667 mL= V₂

Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.

416.7 mL ≈V₂

The volume of the balloon at 250 K is approximately 416.7 milliliters.

5 0

2 years ago

When a solution of ammonium sulfate is added to a

Artist 52 [7]

Answer:

Explanation:

(NH4)2SO4+Pb(NO3)2...............PbSO4+2NH4NO3

7 0

3 years ago