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Anon25 [30]
2 years ago
5

What increases the transfer of the wind's energy to the water?

Physics
1 answer:
kari74 [83]2 years ago
6 0

Answer:

A, flat water

Explanation:

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the rock of 10 kg is falling near the Earth's surface.assume that g =10N/kg and the is no air resistance. what is the accelerati
Ivanshal [37]

Answer:

kya faltu sawal h repetitive g=10N/kg

5 0
3 years ago
Water enters a typical garden hose of diameter 0.016 m with a velocity of 3 m/s. Calculate the exit velocity of water from the g
Vladimir79 [104]

Answer:

v₂ = 306.12 m/s

Explanation:

We know that the volume flow rate of the water or any in-compressible liquid remains constant throughout motion. Therefore, from continuity equation, we know that:

A₁v₁ = A₂v₂

where,

A₁ = Area of entrance pipe = πd₁²/4 = π(0.016 m)²/4 = 0.0002 m²

v₁ = entrance velocity = 3 m/s

A₂ = Area of nozzle = πd₂²/4 = π(0.005 m)²/4 = 0.0000196 m²

v₂ = exit velocity = ?

Therefore,

(0.0002 m²)(3 m/s) = (0.0000196 m²)v₂

v₂ = (0.006 m³/s)/(0.0000196 m²)

<u>v₂ = 306.12 m/s</u>

5 0
3 years ago
Ditto sound waves espace room answers please I need this urgently ​
lord [1]

The actual question should be did the sound waves escape room?

Yes they can escape the room

  • Sound always needs a medium to travel through
  • If you close the room form all where that even air can't go outside you will be able to hear no sound coming from room .
6 0
2 years ago
Sunspots are dark because ___________. a. the strong magnetic field inhibits the currents of hot gas rising from below. b. of sh
maxonik [38]

Answer:

a) the strong magnetic field inhibits the currents of hot gas rising from below.

Explanation:

Sunspots are dark because they are a little cooler than the photo sphere.

The magnetic field inhibits the strong rising currents of hot gas,allowing it to cool the surface.

4 0
3 years ago
A steel ball bearing with a radius of 1.5 cm forms an image of an object that has been placed 1.1 cm away from the bearing’s sur
Nonamiya [84]

Answer:

Check the explanation

Explanation:

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

The image is virtual

The image is upright

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

Kindly check the diagram in the attached image below.

5 0
3 years ago
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