B
Assume north and east as two sides of a right angled triangle. magnitude of the distance is then given by the length of the hypotenuse which is
where a = 1.2 km north
and b = 1.6 km east
magnitude = 2 km
Direction is given by the angle between them, that is atan(a/b) = 36.86 deg north of east = 53.1 deg east of north.
The initial velocity of the cat is 56.6 m/s
Explanation:
The motion of the cat is a projectile motion, consisting of:
- a uniform horizontal motion with constant velocity
- a vertical accelerated motion with constant acceleration (free fall)
We start by analyzing the vertical motion, to find the time it takes for the cat to reach the ground. We use the following suvat equation:
where we have (choosing downard as positive direction)
s = 125 m is the vertical displacement of the cat
u = 0 is the initial vertical velocity
t is the time taken to reach the ground
is the acceleration of gravity
Solving for t, we find
Now we can analzye the horizontal motion. Since the motion is uniform and the horizontal velocity is constant, it is given by
where
d = 286 m is the horizontal distance travelled
t = 5.05 s is the time taken
Solving the equation,
Learn more about projectile motion:
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