Question

An object was released from rest at height of 1.65 m with respect to ground. Determine the time it takes the object to reach the ground. (g = 9.80 m/s

Answer 1

Answer:

The time taken by the object to reach the ground is 0.58 seconds.

Explanation:

Given that,

An object was released from rest at height of 1.65 m with respect to ground. We need to find the time taken by the object to reach the ground. Initial speed of the object is 0 as it is at rest. It will move downward under the action of gravity such that, the distance covered by the object is given by :

$d=ut+\dfrac{1}{2}gt^2$

$d=\dfrac{1}{2}gt^2$

$t=\sqrt{\dfrac{2d}{g}}$

$t=\sqrt{\dfrac{2\times 1.65}{9.8}}$

t = 0.58 seconds

So, the time taken by the object to reach the ground is 0.58 seconds. Hence, this is the required solution.