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xxMikexx [17]
3 years ago
9

What is the net force?

Physics
2 answers:
aliina [53]3 years ago
8 0
400N ...... fkwnfjfjwjdpgnber
yKpoI14uk [10]3 years ago
7 0
400N wusiueuwiwiwiwiss
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the focal length of a simple magnifier is 8.50 cmcm . assume the magnifier to be a thin lens placed very close to the eye.
Igoryamba

When the object is at the focal point the angular magnification is 2.94.

Angular magnification:

The ratio of the angle subtended at the eye by the image formed by an optical instrument to that subtended at the eye by the object when not viewed through the instrument.

Here we have to find the angular magnification when the object is at the focal point.

Focal length = 6.00 cm

Formula to calculate angular magnification:

Angular magnification = 25/f

                                            = 25/ 8.5

                                             = 2.94

Therefore the angular magnification of this thin lens is 2.94

To know more about angular magnification refer:: brainly.com/question/28325488

#SPJ4

5 0
1 year ago
What a measurement? Write down t its importance inn an our daily life.​
balu736 [363]

Answer:

Time, size, distance, speed, direction, weight, volume, temperature, pressure, force, sound, light, energy—these are among the physical properties for which humans have developed accurate measures, without which we could not live our normal daily lives. Measurement permeates every aspect of human life.

8 0
3 years ago
Determine the acceleration due to gravity?
MissTica
That's a weird graph, but judging from the units the acceleration is the slope of the graph.

a = (0.8 - 0.3)/(0.16 - 0.055) = 4.76 m/s²
8 0
3 years ago
If John mows 11.5 meters of lawn from east
Oksanka [162]
I believe it would be 1.6 East
8 0
3 years ago
A 75.0-kg person climbs stairs, gaining 2.50 m in height. Find the work done to accomplish this task.
ololo11 [35]

Answer:

W=1837.5J

Explanation:

A force exerts work when there is a displacement of its point of application in the direction of that force. Therefore, the work done by a system is defined as the inner product between the applied force and the displacement:

W=\vec{F}\cdot \vec{d}\\W=Fcos\theta d

In this case, we have:

F=mg\\h=dcos\theta

So, replacing this:

W=mgh\\W=75kg*9.8\frac{m}{s^2}*2.5m\\W=1837.5J

4 0
4 years ago
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