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xxMikexx [17]
4 years ago
9

What is the net force?

Physics
2 answers:
aliina [53]3 years ago
8 0
400N ...... fkwnfjfjwjdpgnber
yKpoI14uk [10]3 years ago
7 0
400N wusiueuwiwiwiwiss
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On an alien planet, a simple pendulum of length 0.300 m has oscillation frequency 0.709 Hz. Find the period of the pendulum. Fin
sweet [91]

Answer:

1.41s

5.95m/s

0.2746m

Explanation:

The time period

T = 1/f

= 1/0.709s

= 1.41 seconds

We have

T = 2π√l/g

T² = 4π²l/g

g = 4π²l/T²

g = 4x3.14²x0.300/1.41²

g = 5.95m/s² this is the acceleration due to gravity.

Then the time period of the glide

T2 = 2π√m/k

Length of pendulum = l

Time period T

T2 = 2π√l/g

Then T1 = T2

2π√m/k = 2π√l/g

M/k = l/g

L = g.m/k

L = 5.95x0.450/9.75

L = 0.2746

This must be the length of the simple pendulum

8 0
3 years ago
Using information about natural laws, explain why some car crashes produce minor injuries and others produce catastrophic injuri
kicyunya [14]
The forces in some car crashes are greater than others; therefore, the body can be more severely injured by greater and more powerful forces. I hope this helped! :^)
7 0
3 years ago
A 6.9-kg wheel with geometric radius m has radius of gyration computed about its mass center given by m. A massless bar at angle
Vilka [71]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is  \alpha =2.538 \  rad/s^2

Explanation:

From the question we are told that

  The mass of the wheel is  m =  6.9  kg

   The radius is  r =  0.69 \  m

    The radius of gyration is  k_G = 0.4\  m

    The angle is  \theta = 47^o

    The force which the massless bar is subjected to F = 22.5 \  N

Generally given that the wheels rolls without slipping on the flat stationary ground surface, it implies that  point A is the  center of rotation.

  Generally the moment of  inertia about A is mathematically represented as

     I_a =  I_G + M* r^2

Here I_G is the moment of inertia about G with respect to the radius of gyration  which is mathematically represented as

    I_G =  M *  k_G

=>I_a = k_G*  M + M* r^2

=>I_a =0.4 * 6.9  + 6.9 * 0.69^2

=>I_a =6.045 \  kg \cdot m^2

Generally the torque experienced by the wheel  is mathematically represented as

       \tau =  F *  cos (47)

=>     \tau =  22.5 *  cos (47)

=>     \tau =  15.34 \ kg \cdot m^2 \cdot s^{-2}

Generally this torque is also mathematically represented as

     \tau = I_a * \alpha

=>   15.34  =  6.045 * \alpha

=>   \alpha =2.538 \  rad/s^2

4 0
3 years ago
Caitlin is riding her bike. Which of the following statements tells what is happening?
gtnhenbr [62]
What are the following statements? If there's one that mention a description of current action, or motion, that's your answer.
8 0
4 years ago
In order to measure current in a circuit, the multi-meter needs to be placed in __A__ , while when measuring voltage, the multi-
lakkis [162]

Answer:

A- series B- parallel

Explanation:

In order to measure current in a circuit, the multi-meter needs to be placed in series with the circuit while when measuring voltage, the multi-meter needs to be placed in parallel with the circuit.

It should be however noted that the same current flows in a series connected circuit and same voltage flows through loads connected in parallel. The ammeter is placed in series with the load to ensure that same value of currents is flowing in both the ammeter and loads(since same current flows in series connected circuit elements and all the amount of voltage must be made to appear on the load for the current to be measured accurately.

Voltmeter is connected in parallel to the load due to high value of current possessed by the voltmeter. The parallel connection will cause the current flowing through the voltmeter to reduce to zero so that it won't have effect (increase) on the amount of current initially on the resistor thereby measuring the exact amount of voltage on the load.

3 0
4 years ago
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