Answer: -property
Explanation: Transparency is a property of matter.
Spectroscopy be used to distinguish between the following is the compound B has a peak at 3200 – 3500 cm⁻¹ in its IR spectrum.
<h3>What is spectroscopy?</h3>
Spectroscopy is the study of emission or absorption of light. It is used to study the structure of atoms and molecules.
The three types of spectroscopy are:
- atomic absorption spectroscopy (AAS)
- atomic emission spectroscopy (AES)
- atomic fluorescence spectroscopy (AFS)
Thus, the correct option is B, the compound B has a peak at 3200 – 3500 cm⁻¹ in its IR spectrum.
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<h3>Answer:</h3>
Molecular Formula = S₂O₂ (Disulfur Dioxide)
<h3>Solution:</h3>
Molecular formula is calculated by using following formula,
Molecular Formula = n × Empirical Formula ---- (1)
Also, n is given as,
n = Molecular Weight / Empirical Formula Weight
Molecular Weight = 96.13 g.mol⁻¹
Empirical Formula Weight = 32.06 (S) + 16.0 (O) = 48.06 g.mol⁻¹
So,
n = 96.13 g.mol⁻¹ ÷ 48.06 g.mol⁻¹
n = 2.0002 ≈ 2
Putting Empirical Formula and value of "n" in equation 1,
Molecular Formula = 2 × SO
Molecular Formula = S₂O₂ (Disulfur Dioxide)
Answer:
<em>The correct option is the structure in the option D. </em>
Explanation:
Ammonia contains a single nitrogen atom bonded to three hydrogen atoms.
The structure present in option A shows a single nitrogen atom bonded with a single hydrogen atom hence it is not correct.
The structure in option B shows a nitrogen atom bonded to four hydrogen atoms hence it is also not correct.
The structure in option C shows a nitrogen atom bonded to two hydrogen atoms hence it is also not correct.
The structure in option D shows a nitrogen atom bonded to three hydrogen atoms which is the correct structure of ammonia (NH3).