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3 years ago

Press the yellow reset button at the bottom of the simulation screen. Under Constant Parameter, select Volume. Again,

Chemistry

1 answer:

mr Goodwill [35]3 years ago

4 0

Answer:

300 0.24

600 0.46

900 0.70

1200 0.95

1500 1.20

Explanation: correct on behavior gasses tutorial

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Need help in chemistry with these 10 questions please. 80 points well be given.

Kisachek [45]

Answer:

See the attachment for the filled in chart.

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4 years ago

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3 Feas) + 4H20lg) Foog(s) + 4H₂ (g)

Nonamiya [84]

Answer:

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4 years ago

Which property of water causes water drops to bead on a freshly waxed car?

astraxan [27]

Answer:

Cohesive forces are greater than adhesive forces

Step-by-step explanation:

The attractive forces between water molecules and the wax on a freshly-waxed car (adhesive forces) are quite weak.

However, there are strong attractive forces (cohesive forces) between water molecules.

The water molecules are only weakly attracted to the wax, so the cohesive forces pull the water molecules together to form beads .

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4 years ago

alculate the standard enthalpy of formation of ethanoic acid given that the standard enthalpy of combustion for carbon is –394 k

agasfer [191]

Answer:

The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.

Explanation:

$C(g)+O_2(g)\rightarrow CO_2(g),\Delta H_{1, comb}=-394 kJ/mol$ ...[1]

$H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l),\Delta H_{2, comb}=-286 kJ/mol$ ..[2]

$CH_3COOH(l)+2O_2(g)\rightarrow 2CO_2(g)+2H_2O(l),\Delta H_{3, comb}=-876 kJ/mol$ ..[3]

The standard enthalpy of formation of ethanoic acid :

$2C(g)+2H_2(g)+O_2(g)\rightarrow CH_3COOH, \Delta H_{4}=?$ ..[4]

Using Hess's law to calculate :

2 × [1] + 2 × [2] - [3] = [4]

$\Delta H_4=2\times (-394 kJ/mol)+2\times (-286 kJ/mol) - (-876 kJ/mol)$

$=\Delta H_4=-484 kJ/mol$

The standard enthalpy of formation of ethanoic acid is -484 kJ/mol.

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3 years ago

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VLD [36.1K]

Answer:

B i think

Explanation:

google lol but could be wrong

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4 years ago

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